Answer:
The price of 1 adult ticket is 12 dollars, and the price of a ticket for one student is 7 dollars
Step-by-step explanation:
Make a system of equations for the two days that the play was shown.
Let x = the price of an adult ticket
Let y = the price of a student ticket
For the first day:
<h3>9x+8y=164</h3>
For the second day:
<h3>2x+7y=73</h3>
Now, we can solve using the elimination method. Multiply the first equation by 2 and the second equation by 9. Then swap the order of the equations.
<h3>18x+63y= 657</h3><h3>-</h3><h3>18x+16y= 328</h3><h3>0x+ 47y= 329</h3><h3>divide both sides by 47</h3><h3>y = 7</h3><h3>Plug in 7 for y for the 2nd equation</h3><h3>2x+7(7)=73</h3><h3>2x+49=73</h3><h3>subtract 49 from both sides</h3><h3>2x= 24</h3><h3>divide both sides by 2</h3><h3>x = 12 </h3><h3>Check:</h3><h3>2(12)+7(7)=73</h3><h3>24+49= 73!</h3>
The answer is D. -3 because y=-3x the -3 is the slope.
Answer:dy/DX=log3(2x-1).2
Step-by-step explanation:
Let u be 2x-1
Then derivative of u is 2
Therefore dy/DX=log3(2x-1).2
Let
![r](https://tex.z-dn.net/?f=r)
be the common ratio between terms. Then
![-2.88=4r\implies r=-0.72](https://tex.z-dn.net/?f=-2.88%3D4r%5Cimplies%20r%3D-0.72)
Now denote the
![n](https://tex.z-dn.net/?f=n)
th partial sum of the series by
![S_n=4-2.88+2.0736-1.492992+\cdots+4(-0.72)^{n-1}+4(-0.72)^n](https://tex.z-dn.net/?f=S_n%3D4-2.88%2B2.0736-1.492992%2B%5Ccdots%2B4%28-0.72%29%5E%7Bn-1%7D%2B4%28-0.72%29%5En)
Multiply both sides by
![-0.72](https://tex.z-dn.net/?f=-0.72)
, then subtract from the above to get
![S_n-(-0.72S_n)=4-4(-0.72)^{n+1}](https://tex.z-dn.net/?f=S_n-%28-0.72S_n%29%3D4-4%28-0.72%29%5E%7Bn%2B1%7D)
![1.72S_n=4(1-(-0.72)^{n+1})](https://tex.z-dn.net/?f=1.72S_n%3D4%281-%28-0.72%29%5E%7Bn%2B1%7D%29)
![S_n=2.32558(1-(-0.72)^{n+1})](https://tex.z-dn.net/?f=S_n%3D2.32558%281-%28-0.72%29%5E%7Bn%2B1%7D%29)
As
![n\to\infty](https://tex.z-dn.net/?f=n%5Cto%5Cinfty)
, you're left with