All categories

3 years ago

Pls help with math ASAP

Mathematics

1 answer:

9966 [12]3 years ago

7 0

I think 6,1 and the upper point is -6,11

You might be interested in

If A = (0, 0) and B = (8, 2), what is the length of AB?

dezoksy [38]

8, 2 because A doesn't add anything.

5 0

3 years ago

tresset_1 [31]

A and D because it is basically saying 3:36 so when you simplify it comes down to 1:12

8 0

3 years ago

Read 2 more answers

PLEASE HELP ME ASAP - WILL GIVE BRAINLIEST - 20 POINTS! THANKS!

ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

You switch the y and x and solve for y.

y = 2x + 5

becomes

x = 2y + 5

Subtract 5 on both sides.

x - 5 = 2y

Divide 2 on both sides.

(x - 5) / 2 = y

7 0

4 years ago

Read 2 more answers

Can someone help me with this question.

Korolek [52]

Answer:

lesser x = -4

greater x = 1

Step-by-step explanation:

here's the solution :-

=》

${x}^{2} + 3x - 4 = 0$

=》

${x}^{2} + 4x - x - 4$

=》

$x(x + 4) - 1(x + 4)$

=》

$(x + 4)(x - 1)$

now, there are two cases

case 1) where x + 4 = 0

=》x = -4

case 2) where x - 1 = 0

=》x = 1

6 0

3 years ago

Read 2 more answers

A rocket is launched from a tower. The height of the rocket, y in feet is related to the time after launch, x in seconds, by the

gizmo_the_mogwai [7]

Step-by-step explanation:

The height of the rocket y in feet is related to the time after launch, x in seconds, by the given equation i.e.

$y=-16x^2+165x+78$ ......(1)

It is required to find the maximum height reached by the rocket. For maximum height put $\dfrac{dy}{dx}=0$ .

So,

$\dfrac{d(-16x^2+165x+78)}{dx}=0\\\\-32x+165=0\\\\32x=165\\\\x=5.15\ s$

Put x = 5.15 in equation (1).

$y=-16(5.15)^2+165(5.15)+78\\\\y=503.39\ m$

So, the maximum height reached by the rocket is 503.39 m.

5 0

4 years ago