Answer: 85 or 85% or 85/100
Step-by-step explanation:
This is because there are a total of 100 squares in the grid, and out of those 100 there are 85 squares shaded in. So the model best represents 85, 85%, or 85/100. These answers are dependent on what choices you have for the possible answer.
<h2>
Answer:</h2>
a)
The probability that both televisions work is: 0.42
b)
The probability at least one of the two televisions does not work is:
0.5833
<h2>
Step-by-step explanation:</h2>
There are a total of 9 televisions.
It is given that:
Three of the televisions are defective.
This means that the number of televisions which are non-defective are:
9-3=6
a)
The probability that both televisions work is calculated by:

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.
and the total outcome is the selection of 2 televisions from a total of 9 televisions)
Hence, we get:

b)
The probability at least one of the two televisions does not work:
Is equal to the probability that one does not work+probability both do not work.
Probability one does not work is calculated by:

and the probability both do not work is:

Hence, Probability that atleast does not work is:
0.5+0.0833=0.5833
Answer:
14+28i
Step-by-step explanation:
Answer:
x = 1.14
Step-by-step explanation:
3(2x - 1) + 7 = 6x - 3 - 2(-4x) [Given Equation]
6x - 3 + 7 = 6x - 3 + 8x [Distributive Property]
6x + 4 = 14x - 3 [Combine like-terms]
-8x + 4 = -3 [Subtraction Property of Equality]
-8x = -7 [Subtraction PoE]
x = 1.14 [Division PoE]
Answer:

Step-by-step explanation:
To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.

<em>Remove the fraction by multiplying (d +3) on both sides:</em>

<em>Expand</em><em>:</em>
<em>
</em>
<em>Bring</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>move</em><em> </em><em>the</em><em> </em><em>others</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>:</em>

<em>Factorise</em><em> </em><em>d</em><em> </em><em>out</em><em>:</em>
<em>
</em>
<em>Divide</em><em> </em><em>by</em><em> </em><em>(</em><em>c</em><em> </em><em>+</em><em>1</em><em>)</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
<em>
</em>