Answer:
a) a^6+6a^4b+15a^2b^2+20b^3+15(b^4/a^2)+6(b^5/a^4)+(b/a)^6
b) 20
c) a^6+6a^4+15a^2+20+15/a^2+6/a^4+1/a^6
Step-by-step explanation:
(a+b/a)^6=a^6+6a^5(b/a)+15a^4(b/a)^2+20a^3(b/a)^3+15a^2(b/a)^4+6a(b/a)^5+(b/a)^6
a^6+6a^4b+15a^2b^2+20b^3+15(b^4/a^2)+6(b^5/a^4)+(b/a)^6
b) the coefficient of b^3=20
c) if b=1, the expression is
a^6+6a^4+15a^2+20+15/a^2+6/a^4+1/a^6
Answer:
sino me quivoco es 1/53 espero aber ayudado
Answer:
AC/GI=BC/H
Step-by-step explanation:
we know that
The <u>Side-Angle-Side Similarity Theorem </u>states that: If two sides in one triangle are proportional to two sides in another triangle and the included angle in both are congruent, then the two triangles are similar
In this problem the included angle is
∠C≅∠I
therefore
side AC must be proportional to side GI and side BC must be proportional to side HI
so
AC/GI=BC/HI
<em>Verify</em>
substitute the given values
15/9=20/12
15*12=20*9
180=180 -----> is true
therefore
The two sides are proportional
Answer:
The farmer would need 80 posts.
Step-by-step explanation:
If one side of the garden is 10m long, and the garden is a square, we can assume that all 4 sides will be 10m. That makes it 40m in total. Times 40×2 and you get 80.