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zysi [14]
3 years ago
7

Is 4y+4 equivalent to 2y+2

Mathematics
1 answer:
mash [69]3 years ago
6 0

Answer:

no

Step-by-step explanation:

4y + 4 = 4 (y + 1)

2y+2 = 2 (y + 1 )

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A 13 card hand is dealt from a well-shuffled standard 52-card deck. What is the probability that 4 red cards and 9 black cards a
GaryK [48]

The probability that 4 red cards and 9 black cards are dealt is 0.0735.

Let E be the event that 4 red cards and 9 black cards are dealt.

According to the given question.

Number of card hand that is dealt from a well-shuffled standard 52- card deck is 13

Total number of red cards in a well shuffled card deck = 26

Total number of black cards in a well shuffled card = 26

Now, the number of ways to dealt 13 cards = ^{52} C_{13}

Number of ways to dealt 9 black cards = ^{26}C_{9}

And, the number of ways to dealt 4 red cards = ^{26} C_{4}

As, we know that the probability of an event is calculated by taking the ratio of the favorable outcomes to the total number of outcomes.

Therefore, the the probability that 4 red cards and 9 black cards are dealt is given by

P(E) = \frac{^{26}C_{9}\times \ ^{26}C_{4}    }{^{52}C_{13}  }

⇒ P(E) = \frac{\frac{26!26!}{9!4!17!22!} }{\frac{52!}{13!39!} }

⇒ P(E) = 0.0735

Hence, the probability that 4 red cards and 9 black cards are dealt is 0.0735.

Find out more information about probability here:

brainly.com/question/14530583

#SPJ4

3 0
2 years ago
One diagonal of a rhombus has endpoints (-11, -9) and (-5, -3).
valina [46]

Answer:

(-10, -8) and (-6, -4)

Step-by-step explanation:

we know that

The diagonals of a rhombus are perpendicular

If two lines are perpendicular, then the product of their slopes is equal to -1

m1*m2=-1

step 1

Find the slope of the given diagonal

we have

(-11, -9) and (-5, -3)

m=(-3+9)/(-5+11)

m=-6/6=-1

Find the slope of the other diagonal

we have

m1=-1

Find m2

m1*m2=-1

(-1)*m2=-1

m2=1

step 2

Verify the slope of each of the endpoints of the other diagonal

The slope of the other diagonal must be equal to 1

so

case a) (-10, -4) and (-6, -8)

m=(-8+4)/(-6+10)

m=-4/4=-1

therefore

The points of case a) cannot be the end-points of the other diagonal

case b) (-8, -3) and (-5, -6)

m=(-6+3)/(-5+8)

m=-3/3=-1

therefore

The points of case b) cannot be the end-points of the other diagonal

case c) (-8, -4) and (-8, -8)

m=(-8+4)/(-8+8)

m=-4/0 -----> undefined

therefore

The points of case c) cannot be the end-points of the other diagonal

case d) (-10, -8) and (-6, -4)

m=(-4+8)/(-6+10)

m=4/4=1

therefore

The points of case d) can be the end-points of the other diagonal

6 0
3 years ago
PLEASE HELP! (Correct answers only please)
Licemer1 [7]
23440 & 2.344 x 10^4

5 0
3 years ago
Question 11 of 25
Olegator [25]

\\ \sf\longmapsto x+4=\sqrt{8-x}

\\ \sf\longmapsto (x+4)^2=8-x

\\ \sf\longmapsto x^2+16+8x=8-x

\\ \sf\longmapsto x^2+8x-x+16-8=0

\\ \sf\longmapsto x^2+7x+8=0

\\ \sf\longmapsto x^2-8x+x+8

\\ \sf\longmapsto (x-8)(x-1)=0

\\ \sf\longmapsto x=8,-1

Option C

4 0
3 years ago
Read 2 more answers
Divide 13 .024 by 0.36​
NemiM [27]

Answer:

if we divide 13.024 by 0.36

the Ans is 36.17

7 0
3 years ago
Read 2 more answers
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