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3 years ago

Pls help me ASAP plssss!!!

Mathematics

1 answer:

Nataly [62]3 years ago

7 0

Answer:

7. $8

8. coupons offer deals upfront, rebates only offer them after purchase, and sales are short times to drive sales

Step-by-step explanation:

7 work. best buy: 60 - 2 = 40 40 x 4 = 160

Gamestop: 60 x 0.3 = 18 42 x 4 = 168

160 - 168 = -8

$8 dollars saved by Best Buy

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Can someone answer this question, and give me the work?

ladessa [460]

This is the expression
$30x - 40$

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5 0

3 years ago

Please helpppppppppp

GaryK [48]

Answer:

Step-by-step explanation:

Count the number of places it takes to get one place past 3

There are 5 zeros in the given question. That gets you to just before the 3.

Add one more to get past the 3. That makes 5 zeros + 1 more place = 6

Since you are moving right, the 6 is minus. Your answer is 3 * 10^-6

7 0

3 years ago

2(x+9)= [ ]x + [ ] what is the answer I’m struggling in math rb please help!!

Anarel [89]

Answer:

2x+18

Step-by-step explanation:

We can start by distributing the 2 to each term in the parentheses...

2(x)+2(9)

Multiply

2x+18

7 0

2 years ago

Read 2 more answers

Finding an Equation of a tangent Line in Exercise, find an equation of the tangent line to the graph of the function at the give

frutty [35]

Answer:

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

Step-by-step explanation:

to find the tangent line we need to find the derivative of the function g(x).

$g(x) =e^{x^3}$

we know that $\frac{d}{dx}(e^{f(x)})=e^{f(x)}f'(x)$

$g'(x) =e^{x^{3}}(3 x^{2})$

$g'(x) =3 x^{2} e^{x^{3}}$

this the equation of the slope of the curve at any point x and it also the slope of the tangent at any point x. hence, g'(x) can be denoted as 'm'

to find the slope at (-1,1/e) we'll use the x-coordinate of the point i.e. x = -1

$m =3 (-1)^{2} e^{(-1)^{3}}\\m =3e^{-1}\\m=\dfrac{3}{e}$

using the equation of line:

$(y-y_1)=m(x-x_1)$

we'll find the equation of the tangent line.

here (x1,y1) =(-1,1/e), and m = 3/e

$(y-\dfrac{1}{e})=\dfrac{3}{e}(x+1)\\y=\dfrac{3x}{e}+\dfrac{3}{e}+\dfrac{1}{e}\\$

$y=\dfrac{3x}{e}+\dfrac{4}{e}$

this is the equation of the tangent at point (-1,1/e)

3 0

3 years ago

Using the discriminant determine the number of real solutions -4x^2+20x-25=0

seraphim [82]

I think it's c I'm not too sure

5 0

3 years ago

Read 2 more answers