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Ira Lisetskai [31]
2 years ago
13

If the measure of angle AXC =8x-7 and the measure of angle AXB=3x+10 what is the measure of angle AXC?

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
3 0

Answer:

<AXC = 101 degrees.

Step-by-step explanation:

The question says that XB is a bisector which means that <AXB = 1/2 of AXC

You can't do the question if that assumption isn't true.

<AXC  = 8x - 7

<AXB = 3x + 10

3x + 10 = 1/2 ( 8x - 7)     Multiply both sides by 2

2(3x + 10) = 8x - 7         Remove the brackets

6x + 20 = 8x - 7             Add 7 to both sides

6x + 20 + 7 = 8x            Combine

6x + 27 = 8x                  Subtract 6x from both sides

27 = 8x - 6x                  Combine

27 = 2x                          Switch

2x = 27                          Divide by 2

x = 27/2

x = 13.5

AXC = 8x - 7

AXC = 8*13.5 - 7

AXC = 108 -7

AXC = 101

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astraxan [27]

Answer:

Length of XM is 5.5 units.

Step-by-step explanation:

Given △XYZ where MZ is the angle bisector of ∠YZX . we have to find the length of XM.

A triangle with vertices  X, Y, and Z. Side XZ is base. A line segment drawn from Z to M bisects ∠YZX into two parts ∠YZM and ∠XZM.

YZ=7 units, XZ=11 units and YM=3.5 units

By angle bisector theorem which states that an angle bisector of an angle divides the opposite side in two segments that are proportional to the another two sides of the triangle.

Hence, \frac{YM}{MX}=\frac{YZ}{XZ}

⇒ \frac{3.5}{MX}=\frac{7}{11}

⇒ MX=5.5 units.

Hence, length of XM is 5.5 units.


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