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3 years ago

I really need help with this!

Mathematics

1 answer:

mixer [17]3 years ago

8 0

Answer:

3(2 + 9)

Step-by-step explanation:

The numbers 6 and 27 can be written as factored as

6 = 2 * 3

27 = 3 * 3 * 3

The both have one factor of 3 in common.

The greatest common factor (the GCF) of 6 and 27 is 3.

Now we factor out 3. To do that, we divide both 6 and 27 by 3.

6/3 = 2

27/3 = 9

We see that

6 + 27 = 3 * 2 + 3 * 9,

and the common factor of 3 is in both multiplications.

Finally, we factor out the 3, leaving the results of the divisions inside the parentheses.

6 + 27 = 3 * 2 + 3 * 9 = 3(2 + 9)

Answer: 3(2 + 9)

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Write an equation that represents the line

PolarNik [594]

Answer:

y = 2/3x + 4/3

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

7 0

3 years ago

Suppose that the probability a seed will germinate is 85%. What is the probability that 7 of these seeds will germinate when 10

Neporo4naja [7]

Answer: The probability that 7 of these seeds will germinate when 10 are planted is 0.1298 .

Step-by-step explanation:

Let x be the number of seeds germinate .

Since each seed is independent from other , so we can use binomial over here.

Binomial probability formula : $P(X=x)=^nC_xp^x(1-p)^{n-x}$ , where n= total trails and p is the probability of each success.

As per given : p= 0.85 , n= 10

Then, the probability that 7 of these seeds will germinate when 10 are planted will be :-

$P(X=7)=^{10}C_7(0.85)^7(1-0.85)^3\\\\=\dfrac{10!}{7!3!}(0.85)^7(0.15)^3\\\\=0.129833720754\approx0.1298$

Hence, the probability that 7 of these seeds will germinate when 10 are planted is 0.1298 .

5 0

3 years ago

Sydney has a bag of stuffed animals containing, 1 elephant, 4 bears, 3 cats, and 2 dogs. If she randomly selects 1 stuffed anima

torisob [31]

Answer:

2/15

Step-by-step explanation:

Step one:

given data

sample space

1 elephant,

4 bears,

3 cats, and

2 dogs.

sample size= 1+4+3+2= 10

Required:

By selecting without replacement, the probability that she chooses a bear both times

Step two:

the first event= Pr(bear)= 4/10= 2/5

the second event, the sample size is now 9 and the number of bears is now 3

Pr(bear)= 3/9= 1/3

Hence, the probability that she chooses a bear both times

= 2/5*1/3

=2/15

3 0

4 years ago

Ruby wants to estimate the height of a streetlamp post on her block. She stands a certain

ira [324]

Answer: The height of street would be 3.26 feet.

Step-by-step explanation:

Since we have given that

Angle of elevation = 71°

Distance traveled = 12 feet

Angle of elevation becomes 46°.

So, the height of the street lamp post would be

$h=\dfrac{d}{\cot 46^\circ-\cot 71^\circ}\\\\h=\dfrac{12}{0.965-0.344}\\\\h=\dfrac{12}{0.620}\\\\h=3.26\ feet$

Hence, the height of street would be 3.26 feet.

6 0

3 years ago

1. Edgar measures the temperature of a solution at the beginning of an experiment to be 23°F . He monitors the

PIT_PIT [208]

The average change in temperature in each minute would be A) -1.1ºF and B) -1.7ºF.

To A) write an expression that represents the average change in temperature each minute, and B) if Edgar repeats the experiment and finds the average change in temperature each minute is 1 ° F greater in the second trial than in the first trial, to determine what is the average change in temperature each minute in the second trial of the experiment, the following calculations must be performed:

(-2 x 4 + -3 x 3 + 6) / 10 = X

(-8 + -9 + 6) / 10 = X

-11 / 10 = X

-1.1 = X

(-3 x 4 + -4 x 3 + 7) / 10 = X

(-12 + -12 + 7) / 10 = X

-17/10 = X

-1.7 = X

Therefore, the average change in temperature in each minute would be A) -1.1ºF and B) -1.7ºF.

Learn more about averages in brainly.com/question/25818763

5 0

3 years ago