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andre [41]
3 years ago
11

A surgical technique is performed on seven patients. You are told there is a 70% chance of success. Use a table to find the prob

ability the surgery is successful for exactly five patients.
Mathematics
1 answer:
kiruha [24]3 years ago
5 0

Answer:

31.77% probability the surgery is successful for exactly five patients.

Step-by-step explanation:

For each patient, there are only two possible outcomes. Either the surgery is successful, or it is not. The probability of the surgery being successful for a patient is independent of other patients. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A surgical technique is performed on seven patients.

This means that n = 7

You are told there is a 70% chance of success.

This means that p = 0.7

Find the probability the surgery is successful for exactly five patients.

This is P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{7,5}.(0.7)^{5}.(0.3)^{2} = 0.3177

31.77% probability the surgery is successful for exactly five patients.

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