Which term is any number that can be shown as the quotient of two integers
1 answer:
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Answer:
The equation of the line is y = 2x - 3
Step-by-step explanation:
The form of the linear equation is y = m x + b, where
- m is the slope of the line,
- b is the y-intercept (value y at x = 0)
Let us take two points on the line to find its equation
∵ Points (3, 3) and (0, -3) lie on the line
∴ x1 = 3 and y1 = 3
∴ x2 = 0 and y2 = -3
→ Use the rule of the slope above to find m
∵
∴ m = 2
→ Substitute its value in the form of the equation above
∴ y = 2x + b
∵ b is the value of y at x = 0
∵ y = -3 at x = 0
∴ b = -3
→ Substitute it in the equation above
∴ y = 2x + -3
→ Remember (+)(-) = (-)
∴ y = 2x - 3
∴ The equation of the line is y = 2x - 3
Answer:
2, 4
Step-by-step explanation:
Let there are two unknown consecutive pairs of even integers 2n and 2n+2.
If the sum of the reciprocals of those two integers is 3/4, then we can write,
1/2n +1/(2n+2) =3/4 ...... (1)
Solving this above equation we can check whether the integers exist or not.
Now, from equation (1) we get,
1/n +1/(n+1) =3/2
⇒
⇒4n +2 =3n²+3n
⇒3n²-n-2 =0
⇒ (n-1)(3n+2) =0
⇒ (n-1) =0 {Since if (3n+2) =0 then, n will be a negative fraction, which is not possible}
⇒ n=1
∴ 2n =2 and 2n+2 =4
Hence, the two integers are 2, 4. (Answer)