Answer:
1) the genes and chromosomes do not double after each generations because parental sex cells are haploid and only contain one set of chromosomes. During fertilization the two cells fuse to form a diploid zygote with two copies of genes and chromosomes. For example a normal human has 46 chromosomes (2 copies of 23 chromosomes) during reproduction gametes which contain 23 chromosomes (haploid) fuse to form an offspring with the correct number of chromosomes ( 23 + 23 = 46).
2) offspring only receive one set of chromosomes from each parent so to maintain the chromosome number of humans. If this did not happen you would not be the same species.
Question 1
Answer:
D- Different nucleotide combinations code for the same amino acid.
Explanation:
Some amino acid has more than one nucleotide combination coding for it.
Question 2
Answer:
B- Redundancy
Explanation:
Redundancy means that more than one codon is assigned for the coding of most amino acids.
Question 3
Answer:
0%
Explanation:
Since both parents are homozygous dominant and recessive respectively, no crossing can give the homozygous dominant as all offspring are heterozygous.
Question 4
Answer:
Homozygous.
Explanation:
The genotype 'dd' is homozygous since the two letters are both in the lower case.
Question 5
Answer:
25%
Question 6
Answer:
Dihybrid cross
Bacterial translation is initiated in three steps. In the final step, the large ribosomal subunit binds to the mRNA.
The ribosome's translation of an mRNA molecule occurs in three stages: initiation, elongation, and termination. The small ribosomal subunit binds to the beginning of the mRNA sequence during initiation. Most eukaryotic mRNAs initiate translation by binding Met-tRNAiMet to a 40S subunit, followed by ribosomal attachment at the 5′ end of an mRNA, scanning to the initiation codon, and joining with a 60S subunit to form an 80S ribosome. The stages of translation should be completed in the following order: Initiation, Elongation, and Termination.
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