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3 years ago

6

At Summer camp, 62 percent of the campers decide they want to go swimming instead of hiking. If there are 200 kids at the camp,

how many go swimming?

1 answer:

BartSMP [9]3 years ago

4 0

Answer:

124

Step-by-step explanation:

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The Lane School sold 1,152 granola bars to raise money for digital cameras. All the granola bars were either berry bars or raisi

11Alexandr11 [23.1K]

Answer:

26 boxes of raisin bars

Step-by-step explanation:

Take the total bars sold 1152 then subtract the berry bars 528 and you'll get 624. Next you'll divide the 624 by 24 because that's how many that's in a full box. Finally you'll get your answer of 26 boxes.

1152-528=624 ➗ 24 = 26

7 0

3 years ago

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

<u><em>Find the radius of the sphere with a 5.50-meter circumference</em></u>

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

<u><em>Find the radius of the sphere with a 7.85-meter circumference</em></u>

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN

MrRa [10]

Since the distance of MN is 31 and we have a distance of ML of h -15 and LN of 2h – 8, therefore

ML + LN = h -15 + 2h – 8 = 31

h = 18

substituting the value of h to the expression for LN obtaining

LN = 2h – 8

LN = 2(18) – 8

LN = 28

Therefore the length of the segment LN is 28 units

7 0

3 years ago

What's the volume to this prism?

DIA [1.3K]

Answer:

36 cubic inch

Step-by-step explanation:

The formula for the volume of a rectangular prism is:

$V=whl$

----------------------------------------------------------------------------------------------------------------

So:

6 × 3 × 2 = 36

----------------------------------------------------------------------------------------------------------------

Have a good day :)

8 0

3 years ago

An item is regular priced is at $60. It is on sale for 55% off the regular price. What is the sale price?

dalvyx [7]

0.550×$60 = $33
$60- $33= $27.00
Therefore, the answer is $27

5 0

3 years ago

Read 2 more answers