Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
you find what they both divide by and then divide each one and then you keep doing that until you cant no more
5:3. Simply by the common factor which is 6. 30 divided by 6 is five. 18 divided by 6 is 3. Therefore the simplest form is 5:3
Answer:
120
Step-by-step explanation:
