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Lady_Fox [76]
3 years ago
8

3/2-5/6-2/9 WILL GIVE BRAINLIEST THANKS AND 5 STARS FOR THE 1ST CORRECT ANSWER

Mathematics
2 answers:
Sloan [31]3 years ago
7 0

Answer:

0.44444444444

Step-by-step explanation:

thank me later

Serga [27]3 years ago
4 0

Answer:

4/9

Step-by-step explanation:

It’s basic math UwU

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In a survey, a group of students were asked to name their favorite day of the week. There were 8 students who chose “other”.
lara [203]
5 % of the students choose other. 95% choose either Saturday or Sunday. 
Let x be the number of students who participated.

(5/100) * x = 8  Multiply both sides by 100
5 * x = 8*100
5*x = 800  Divide by 5
x = 800/5
x = 160 students participated in the survey <<<<< Answer
6 0
3 years ago
What is the length of BC? If your answer is not an integer, leave it in simplest radical form.
IrinaVladis [17]

Answer: BC = 16√2 ft

Step-by-step explanation:

Triangle ABC is a right angle triangle. From the given right angle triangle, BC represents the hypotenuse of the right angle triangle.

With m∠W as the reference angle,

AB represents the adjacent side of the right angle triangle.

AC represents the opposite side of the right angle triangle.

To determine the length of BC, we would apply the Sine trigonometric ratio which is expressed as

Sin θ, = opposite side/hypotenuse. Therefore,

Sin 45 = 16/BC

√2/2 = 16/BC

BC = 16/(√2/2) = 16 × 2/√2

BC = 32/√2

Rationalizing the denominator, it becomes

BC = 32/√2 × √2/√2

BC = 32√2/2

BC = 16√2 ft

8 0
3 years ago
Please help!!!!!!!!!
Natali [406]

Answer: $432

Step-by-step explanation: If he marks up the price by 80% then you multiply the price (240) times 0.8, which is 192. That is how much he marks it up -- $192. SO then you add how much he marks it up to the original price of $242 which is $432.

6 0
3 years ago
Factorise the following. x²-4​
slava [35]

(x-2)(x+2) is factorize is given eq

7 0
3 years ago
Evaluate the following integral using trigonometric substitution.
wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function \int\limits {\sqrt{a^{2} -x^{2} } } \, dx, using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as asin \theta i.e x = a sin\theta.

All integrals in the form \int\limits {\sqrt{a^{2} -x^{2} } } \, dx are always evaluated using the substitute given where 'a' is any constant.

From the given integral, \int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx where a = 7 in this case.

The substitute will therefore be   x = 7 sin\theta

2.) Given x = 7 sin\theta

\frac{dx}{d \theta} = 7cos \theta

cross multiplying

dx = 7cos\theta d\theta

3.) Rewriting the given integral using the substiution will result into;

\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta  } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)}   } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)}   }}} \, 7cos\theta d\theta\\

= \int\limits343 cos^{2}  \theta \, d\theta

8 0
3 years ago
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