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faust18 [17]
4 years ago
7

I need help with this magic number puzzle

Mathematics
1 answer:
Delicious77 [7]4 years ago
7 0
You need a better camera

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From the set {200, 210, 388}, use substitution to determine which value of x makes the equation true.
IrinaK [193]

Answer:

b

Step-by-step explanation:

because x= 386

3 0
3 years ago
Read 2 more answers
− 2/3 ​ a+ 6 /5 ​ a− 6 /1
muminat

Answer:

=8/15a−6

Step-by-step explanation:

−2/3a+6/5a−6/1=−2/3a+6/5a+−6

=−2/3a+6/5a+−6=(−2/3a+6/5a)+(−6)=8/15a+−6

7 0
3 years ago
Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?
NNADVOKAT [17]

f(x)= -99.4x + 198.8

f(1) = -99.4*1 + 198.8 = 99.4

f(2) = -99.4*2 + 198.8 = 0

f(3) = -99.4*3 + 198.8 = -99.4

<span>f(4) = -99.4*4 + 198.8 = -198.8
</span>

5 0
4 years ago
Read 2 more answers
Given that f(x) = x2 + 2x + 3 and g(x) = quantity of x plus four, over three , solve for f(g(x)) when x = 2.
Sidana [21]
f(x)=x^2+2x+3
g(x)=\frac{x+4}{3}
f(g(x))=(\frac{x+4}{3})^2+2(\frac{x+4}{3})+3
f(g(x))=\frac{x^2+8x+16}{9}+\frac{2x+8}{3}+3
f(g(2))=\frac{2^2+8(2)+16}{9}+\frac{2(2)+8}{3}+3
f(g(2))+\frac{4+16+16}{9}+\frac{4+8}{3}+3
f(g(2))=\frac{36}{9}+\frac{12}{3}+3
f(g(2))=4+4+3
f(g(2)=11

Check:
g(2)=(2+4)/3=2
f(2)=2^2+2(2)+3=4+4+3=11  Checks. 
4 0
3 years ago
Read 2 more answers
Hello everyone.
lina2011 [118]

Answer:

I Don't know either

Step-by-step explanation:

I know

8 0
3 years ago
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