Answer:
From the question, Stacey deposits $2600 six times over a thirty year period since she makes the deposit every five years. Her amount accures by the formular. A = P(1+r/n)^nt. Where her principal P = $2,600. Rate, r =6% =0.06. Time = 30 years and the period of compounding per unit time, n = 6 years. So we have A =2, 600(1+(0.06/6))^(6*30) = 2, 600 (1 + 0.01)^(180) = 2600* 5.9958 = $15, 587. To the nearest cent we have $15, 590.
Step-by-step explanation:
:)
Answer:
The answer is D
Since you want to put an equal amount of glue in to 6 containers, the only thing you need to do is to divide 1/2 by 6 and the result is 1/12
Answer:
Step-by-step explanation:
The question is incomplete. The complete question is:
A production line operation is designed to fill cartons with laundry detergent to a mean weight of 32 ounces. A sample of cartons is periodically selected and weighed to determine whether under filling or overfilling is occurring. If the sample data lead to a conclusion of under filling or overfilling, the production line will be shut down and adjusted to obtain proper filling.
A. Formulate the null and alternative hypotheses that will help in deciding whether to shut down and adjust the production line.
B. Comment on the conclusion and the decision when H0 cannot be rejected.
C. Comment on the conclusion and the decision when H0 can be rejected.
Solution:
A) We would set up the hypothesis. Under filling or over filling means two ways. Thus, it is a two tailed test
For null hypothesis,
H0: μ = 32
For alternative hypothesis,
H1: μ ≠ 32
B) if H0 cannot be rejected, it means that there was insufficient evidence to reject it. Thus, it would be concluded that the production line operation filled the cartons with laundry detergent to a mean weight of 32 ounces.
C) There was sufficient evidence to reject the null hypothesis. Thus, it can be concluded that there was under filling or over filling.
Answer:
G is your answer
Step-by-step explanation:
Answer:
population of 1st city =660,000
Step-by-step explanation:
Let the population of second city be x
given that
population of the first city is equal to 32% of the population of the second city
Therefore
population of 1st city = 32% of the population of the second city
32% of x = (32/100)*x
total population of two cities = x + (32/100)*x = (100x+32x)/100 = 132x/100
Also, population of two cities = 660000
thus,
132x/100 = 660000
=> 132x = 660000*100 = 66000000
=> x = 66000000/132 = 2,062,500
Thus, population of 2nd city is 2,062,500
population of 1st city = (32/100)*x = 32/100 * 2,062,500 = 660,000
