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2 years ago

48 + 6m use the GCF to rewrite the expression

Mathematics

1 answer:

Mrrafil [7]2 years ago

7 0

Move all terms containing m to the left all other terms to the right 48+-6m=6m+-6m
48+-6m=0

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Answer:

The cubic function is f(x) = (27/32)·x - 3/32·x³ - -9/32·x² - 9/32

Step-by-step explanation:

The given function is f(x) = a·x³ + b·x² + c·x + d

By differentiation, we have;

3·a·x² + 2·b·x + c = 0

3·a·(-3)² + 2·b·(-3) + c = 0

3·a·9 - 6·b + c = 0

27·a - 6·b + c = 0

3·a·(1)² + 2·b·(1) + c = 0

3·a + 2·b + c = 0

a·(-3)³ + b·(-3)² + c·(-3) + d = -3

-27·a + 9·b - 3·c + d = -3...(1)

a + b + c + d = 0...(2)

Subtracting equation (1) from equation (2) gives;

28·a - 8·b + 4·c = 3

Therefore, we have;

27·a - 6·b + c = 0

3·a + 2·b + c = 0

28·a - 8·b + 4·c = 0

Solving the system of equations using an Wolfram Alpha gives;

a = -3/32, b = -9/32, c = 27/32 from which we have;

a + b + c + d = 0 3 × (-3/32) + 2 × (-9/32) + (27/32) + d = 0

d = 0 - (0 3 × (-3/32) + 2 × (-9/32) + (27/32)) = -9/32

The cubic function is therefore f(x) = (-3/32)·x³ + (-9/32)·x² + (27/32)·x + (-9/32).

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Answer:

I need the values of either X or Y to solve this. I can solve for what X is though.

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A: X = -12

B: X =78

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3 years ago

On the following number line, two rational numbers are graphed.Represent the two numbers as fractions (or mixed numbers) in lowe

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The first graphed rational number is at the middle of -2 and -1, thus the number represented is $-1 \frac{1}{2}$

The second graphed number is five out of six places from from 0 to 1, thus the number graphed is $0+ \frac{5}{6} = \frac{5}{6}$

The difference between the two numbers can be represented as
$-1 \frac{1}{2} - \frac{5}{6}$
or
$\frac{5}{6} -(-1 \frac{1}{2} )= \frac{5}{6} +1 \frac{1}{2}$

To find the difference,

$-1 \frac{1}{2} - \frac{5}{6} \\ \\ =-1 \frac{3+5}{6} \\ \\ =-1 \frac{8}{6} =-2 \frac{2}{6} \\ \\ =-2 \frac{1}{3}$

Also,

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3 years ago

48 + 6m use the GCF to rewrite the expression​

48 + 6m use the GCF to rewrite the expression