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3 years ago

48 + 6m use the GCF to rewrite the expression

Mathematics

1 answer:

Mrrafil [7]3 years ago

7 0

Move all terms containing m to the left all other terms to the right 48+-6m=6m+-6m
48+-6m=0

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If m angle ABD=79 degrees , what are m angle ABC and m angle DBC

gulaghasi [49]

Answer:

m<ABC = 45

m<DBC = 34°

Step-by-step explanation:

Given:

m<ABD = 79°

m<ABC = (8x - 3)°

m<DBC = (5x + 4)°

Step 1: Generate an equation to find the value of x

m<ABC + m<DBC = m<ABD (angle addition postulate)

(8x - 3) + (5x + 4) = 79

Solve for x

8x - 3 + 5x + 4 = 79

13x + 1 = 79

Subtract 1 from both sides

13x + 1 - 1 = 79 - 1

13x = 78

Divide both sides by 13

x = 6

Step 2: find m<ABC and m<DBC by plugging the value of x into the expression of each angle

m<ABC = (8x - 3)°

m<ABC = 8(6) - 3 = 48 - 3 = 45°

m<DBC = (5x + 4)°

m<DBC = 5(6) + 4 = 30 + 4 = 34°

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4 years ago

Back to school is coming and laura is

sattari [20]

Huh? Are you missing the something

7 0

3 years ago

If x=-4 and y=3 what is the value of x-3y^2 a: -13 b: -31 c: -23 d: -85

Alexandra [31]

Answer:

b -31

Step-by-step explanation:

8 0

3 years ago

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A pole that is 2.5 m tall casts a shadow that is 1.47 m long. At the same time, a nearby tower casts a shadow that is 36.25 m lo

Roman55 [17]

The tower is 61.65 meters tall.

SOLUTION:

Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.

At the same time, a nearby tower casts a shadow that is 36.25 m long.

We have to find height of the tower.

Now, we know that,

$2.5 \mathrm{m} \text { tall } \rightarrow 1.47 \text { long shadow }$

Then, (let it be) n meter tall $\rightarrow$ 36.25 long shadow

So, by cross multiplication method,

$\Rightarrow \frac{2.5}{1.47}=\frac{n}{36.25}$

This can be written as,

$\Rightarrow 36.25 \times 2.5=1.47 \times n \rightarrow 1.47 n=90.625 \rightarrow n=61.649 \rightarrow n=61.65 \text{ m}$

Cross multiplications steps: (To find Single Variable)

Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
Set the two products equal to each other.
Solve for the variable.

6 0

3 years ago

What is the value of fraction 1 over 3x3 + 5.2y when x = 3 and y = 2?

Slav-nsk [51]

Hello from MrBillDoesMath!

Answer:

1/ 91.4

Discussion:

Evaluate 1/ ( 3x^3 + 5.2y) when x = 3, y = 2.

1/ (3 (3)^3 + 5.2(2)) =

1/ ( 3 * 27 + 10.4) =

1/ ( 81 + 10.4) =

1/ (91.4) =

.0109 (approx)

Thank you,

MrB

6 0

4 years ago

48 + 6m use the GCF to rewrite the expression​

48 + 6m use the GCF to rewrite the expression