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prisoha [69]
3 years ago
12

Find the equation of the line that is parallel to y=4x+1 and contains the point (1,1)

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

Find the equation of the line that is parallel to y=4x+1 and contains the point (1,1)

Substitute 1 for x and 1 for y in y=4x+1.

1=4(1)+1

The given point does not make the equation true.

Invalid Point

Step-by-step explanation:

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The ellipse with x-intercepts (2, 0) and (-2, 0); y-intercepts (0, 4) and (0, -4).
masya89 [10]

Answer:

\dfrac{x^2}{4}+\dfrac{y^2}{16}=1

Step-by-step explanation:

If the ellipse has its x-intercepts at points (2, 0) and (-2, 0) and y-intercepts at points (0, 4) and (0, -4), then its symmetric across the y-axis and across the x-axis.

Moreover,

a=2\\ \\b=4

The equation of such ellipse is

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1

Hence, the equation of the ellipse is

\dfrac{x^2}{2^2}+\dfrac{y^2}{4^2}=1\\ \\ \\\dfrac{x^2}{4}+\dfrac{y^2}{16}=1

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Which of the following best describes perpendicular lines?
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