First add 11 and 4 because you need to know how many he had in total 11+4=15 then divide 15 by 3 and then you have you answer 15/3=5.
There are 5 model cars in each pack.
P(getting odd number) = 3/6 = 1/2 ( as there are 3 odds and 3 evens on a die).
P(head) = 1/2
these are multiplied as the 2 events are independent :-
Answer is 1/2 * 1/2 = 1/4
Y^2=x+2
here vertex = (-2,0)
+ AOS =0
Also Y= (x+2)^2
Vertex = -2,0
AOS = x+2 =0
<span>so, in total 4 parabolas are possible with the information provided</span>
Answer:
Answer: I think its 15 but if you could give me answer choices it would be better
But The answer is 15.
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Answer:
what is the question lol
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