Answer:B
Step-by-step explanation:
Answer:

Step-by-step explanation:
<u>Translations</u>
For 




Parent function: 
Translated 2 units right: 
For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

Where:
m: It is the slope of the line
b: It is the cut-off point with the y axis

We have the following points:

Substituting we have:

Thus, the equation is of the form:

We substitute one of the points and find "b":

Finally, the equation is of the form:

Answer:
