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3 years ago

The length of a rectangular flower garden is 9 feet and it’s width is 5 feet how many feet of fencing will be needed

1 answer:

8 0

Use the simple perimeter formula.
P = 2L + 2W
P = 2(9) + 2(5)
P = 19 + 10
P = 29ft

Therefore 29ft of fencing will be needed.

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Find the area of this shape.

Amiraneli [1.4K]

Hi.

I'm going to tell you the process, since I don't have a calculator on me. Don't wanna risk it, lol.

We can break this shake into 2 parts: a rectangle, and a triangle.

To separate them, just calculate the area of the rectangle with 4 km & 3.5 km

Since the triangle's area is half that of the rectangle, all we need to do is divide the area of the rectangle by 2 to get the area of the triangle (it's confusing when in words, eh?)

Once you find the area of both, add them together.

This should get you the area of the shape.

I hope this helped. Once again, please let me know if there are mistakes.

3 0

3 years ago

Please please help!!

shepuryov [24]

Answer:

$\large\boxed{x=0\ and\ x=\pi}$

Step-by-step explanation:

$\tan^2x\sec^2x+2\sec^2x-\tan^2x=2\\\\\text{Use}\ \tan x=\dfrac{\sin x}{\cos x},\ \sec x=\dfrac{1}{\cos x}:\\\\\left(\dfrac{\sin x}{\cos x}\right)^2\left(\dfrac{1}{\cos x}\right)^2+2\left(\dfrac{1}{\cos x}\right)^2-\left(\dfrac{\sin x}{\cos x}\right)^2=2\\\\\left(\dfrac{\sin^2x}{\cos^2x}\right)\left(\dfrac{1}{\cos^2x}\right)+\dfrac{2}{\cos^2x}-\dfrac{\sin^2x}{\cos^2x}=2$

$\dfrac{\sin^2x}{(\cos^2x)^2}+\dfrac{2-\sin^2x}{\cos^2x}=2\\\\\text{Use}\ \sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-(1-\cos^2x)}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-1+\cos^2x}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{1+\cos^2x}{\cos^2x}=2$

$\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{(1+\cos^2x)(\cos^2x)}{(\cos^2x)^2}=2\qquad\text{Use the distributive property}\\\\\dfrac{1-\cos^2x+\cos^2x+\cos^4x}{\cos^4x}=2\\\\\dfrac{1+\cos^4x}{\cos^4x}=2\qquad\text{multiply both sides by}\ \cos^4x\neq0\\\\1+\cos^4x=2\cos^4x\qquad\text{subtract}\ \cos^4x\ \text{from both sides}\\\\1=\cos^4x\iff \cos x=\pm\sqrt1\to\cos x=\pm1\\\\ x=k\pi\ for\ k\in\mathbb{Z}\\\\\text{On the interval}\ 0\leq x$

4 0

2 years ago

What is c3/2 if c equal 4?

Sedbober [7]

Answer:

(4 x 3) / 2

Step-by-step explanation:

3 0

3 years ago

Find the coordinates of the midpoint of the segment with the given pair of endpoints. J(6, 6); K(2, –4)

Levart [38]

Answer:

(4,1)

Step-by-step explanation:

let J(6,6) be x1, y1

let K(2,-4) be x2, y2

midpoint = (x1+x2)/2 , (y1+y2)/2

=(6+2)/2 ,(6-4)/2

= 8/2 ,2/2

=4, 1

3 0

3 years ago

Help need the answer quick

Shalnov [3]

Answer:

6E hope this helps

6 0

2 years ago