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suter [353]
3 years ago
11

Help! Please thank you.

Mathematics
1 answer:
andre [41]3 years ago
6 0

Answer:

4 quotient and 1 is estimate you don't have to thank me later

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i need a picture cuz i dont see any external that apply

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4 years ago
A grid shows the positions of a subway stop and your house. The subway stop is located at (7, -6) and your house is located at (
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Use the distance formula!

d = square root of (x2-x1)^2 + (y2-y1)^2

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7 0
3 years ago
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Sydney took a taxi from her house to the airport. The taxi company charged a pick-up fee of $1.75 per mile. The total fare was $
Sati [7]

The equation is x = 20.85 / 1.75 where x is the number of miles and the number of miles is 11.91 miles.

Given,

Sydney took a taxi from her house to the airport.

The taxi company charged a pick-up fee of $1.75 per mile.

The total fare was $20.85, not including the tip.

We need to write and solve an equation that can be used to determine the number of miles in the taxi ride.

We have,

Taxi fare per mile = $1.75

Total fare = $20.85

Find the number of miles in a total fare of $20.85.

$1.75 = 1 mile

Multiplying by 20.85 on both sides.

20.85 x $1.75 = 20.85 x 1 mile

Dividing by 1.75 on both sides.

(20.85 x $1.75) / 1.75  = (20.85 x 1 mile) / 1.75

$20.85 = 11.91 mile

We see that  11.91 miles will cost $20.85.

Write an equation to show this situation.

x = 20.85 / 1.75

Where x is the number of miles.

we get,

x = 20.85 / 1.75 = 11.91

Thus the equation is x = 20.85 / 1.75 and the number of miles is 11.91 miles.

Learn more about solving an equation to find the number of miles with a rate given per mile here:

brainly.com/question/22582035

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4 0
2 years ago
How could the formula for perimeter be rearranged to find the length of the playground?
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It would be the third response
6 0
3 years ago
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How do I solve a=b/c² for b
Anarel [89]

Answer:

a * c^2 = b

Step-by-step explanation:

you would want to multiply both sides of the equation by c^2

a * c^2 = b

That gets you this formula you can then plug your numbers in

7 0
3 years ago
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