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miskamm [114]
3 years ago
7

The following graph represents an inequality.

Mathematics
1 answer:
Leni [432]3 years ago
8 0

Answer:

Opt. 1 -3 ≤ x ≤ 3

Step-by-step explanation:

Inequalities are regions, the attached picture shows us a region located between -3 and 3, the dots used are solid, this means that the value '3' is include in the region.

Hence the variable is narrowed to -3 and 3.

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A single 6-sided die is rolled. What is the probability of rolling a number
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Answer:

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4 0
3 years ago
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Mandy and her mom are making homemade play-dough. Besides the flour, the recipe calls for 1/4 cup of salt for every 3/4 cup of w
prisoha [69]

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about a half teaspoon

Step-by-step explanation:

4 0
3 years ago
write the product of the expression 5^4 * 5^-7 using a positive exponent, then write the product using a negative exponent
pav-90 [236]

Answer with positive exponent = \left(\frac{1}{5}\right)^3 or  \frac{1}{5^3}

Answer with negative exponent = 5^{-3}

===========================================================

Explanation:

The rule we use is

a^b*a^c = a^{b+c}

If we multiply two exponential expressions with the same base, then we add the exponents.

The base for each is 5. The exponents 4 and -7 add to -3.

This means

5^4*5^{-7} = 5^{4+(-7)} = 5^{-3}

To convert to a positive exponent, we apply the reciprocal to the base. We go from 5, aka 5/1, to 1/5.

So, 5^{-3} = \left(\frac{1}{5}\right)^3 = \frac{1^3}{5^3} = \frac{1}{5^3}

3 0
2 years ago
Two thirds of a number is 46, what is the number
Thepotemich [5.8K]

Answer:

69

Step-by-step explanation:

If 46 is 2/3 then 1/3 should be 23 and 23 times 3 is 69.I hope this helps

5 0
3 years ago
For the function, f(x)=(9x+7)/(2x+4)
AVprozaik [17]
A. f(x)=\frac{9x+7}{2x+4}\\f'(x)=\frac{(9)(2x+4)-(9x+7)(2)}{(2x+4)^2}\\f'(x)=\frac{(18x+36)-(18x+14)}{(2x+4)(2x+4)}\\f'(x)=\frac{22}{4x^2+16x+16}\\f'(x)=\frac{11}{2x^2+8x+8}\\\frac{11}{(2x+4)(x+2)}=0\\\frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty - There are no critical points because the graph is neither continuous nor smooth. There is a discontinuity at x = 2.

B. \frac{1}{(2x+4)(x+2)}=0\\x=-\infty,\infty - The absolute maximum is f(lim⇒-2_-) = infinity. The absolute minimum is f(lim⇒-2_+) = -infinity. This applies to the interval [-10, 7].

C. f(x)=\frac{9x+7}{2x+4}\\f(0)=\frac{9(0)+7}{2(0)+4}\\f(0)=\frac{7}{4}\\f(0)=1.75\\f(5)=\frac{9(5)+7}{2(5)+4}\\f(5)=\frac{45+7}{10+4}\\f(5)=\frac{52}{14}\\f(5)=\frac{26}{7}\\f(5)=3.714 - The absolute maximum is f(5) = 26/7 or 3.714. The absolute mimimum is f(0) = 1.75. This applies to the interval [0, 5]. Proof: graph f(x) at [0, 5] on a graph or graphing calculator.
5 0
3 years ago
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