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harkovskaia [24]
4 years ago
12

Si un joven recorre en su patineta una pista de 200 metros en un minuto. ¿ A que velocidad circula?​

Mathematics
1 answer:
crimeas [40]4 years ago
8 0

Answer:

6.67 metros por segundo

~ Haga 800/120 que equivale a 6.67 porque hay 60 segundos en un minuto y hay dos minutos, entonces 60 veces 2 es igual a 180, luego configure su problema

Espero que esto te ayude:)

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Is multiplying 10 to the power of 3 the same as multiplying by 10 factors of 3
andrew-mc [135]
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7 0
3 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
Your class is having a pizza party. You buy 5 pizzas Each pizz has 4 slices. How many slices is that altogether?​
bixtya [17]

Answer:

20

Step-by-step explanation:

5 x 4 = 20

3 0
2 years ago
Read 2 more answers
Inverse square root (x+3)​
QveST [7]

Answer:

The inverse function is f(x) = x^2 - 3

Step-by-step explanation:

To find the inverse of any function, start by switching the x and f(x) values.

f(x) = √(x + 3)

x = √(f(x) + 3)

Now solve for the new f(x). The result will be your inverse function.

x = √(f(x) + 3)

x^2 = f(x) + 3

x^2 - 3 = f(x)

8 0
3 years ago
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