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kogti [31]
3 years ago
6

You invest 3000 in an account that pays simple interest of 7% for 30 years​

Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer: the amount of interest is $630.00

Step-by-step explanation:

www . webmath . com i used this website to calculate the interest. it was really helpful for me and i hope it helps you! ( had to put it like that so i could submit.

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Y varies directly as x. If x = 15 when y = 20, find x when y = 30.
Goryan [66]

Answer:

22.5

Step-by-step explanation:

y=kx

20=k15

k=1•33

30=1•33x

x=22•5

5 0
3 years ago
What is the answer to 3a+5-x+7x-2a
Black_prince [1.1K]
The answer to your problem is a+6x+5.
4 0
3 years ago
Please help me find out the process to find y for the first three questions and tell me what y is
Sliva [168]

Answer:

1. y = 14.718

2. ??

3. y = 39.794°

Step-by-step explanation:

<em>HINT the side we already know and the side we are trying to find, we use the first letters of their names and the phrase "SOHCAHTOA" to decide which function: </em>

SOH...

 Sine: sin(θ) = Opposite / Hypotenuse

...CAH...

 Cosine: cos(θ) = Adjacent / Hypotenuse

...TOA

 Tangent: tan(θ) = Opposite / Adjacent

1. Sine: sin(θ) = Opposite / Hypotenuse

sin(42°) = y / 22

so on your calculator enter 42 then sin = 0.669

0.669 = y/22      multiply both sides by 22 to get y

y = 14.718

2. is there any other information??

3. The two sides we know are Opposite 40 and Adjacent 48.

SOHCAHTOA tells us we must use Tangent.

Calculate Opposite/Adjacent = 40/48 = 0.833

Find the angle from your calculator using tan-1

Tan y° = opposite/adjacent = 40/48 = 0.833  

tan-1 of 0.833 = 39.794°

7 0
3 years ago
What is this sum about like 3×3 what is that pls tell me
mars1129 [50]
3x3=9


hope this helps
7 0
3 years ago
Read 2 more answers
Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

Now, squaring the equality at the beginning we get that

3=\frac{m^2}{n^2} (1)

which is equivalent to 3n^2=m^2. From this we can deduce that 3 divides the number m^2, and necessarily 3 must divide m. Thus, m=3p, where p is a non negative integer.

Substituting m=3p into (1), we get

3= \frac{9p^2}{n^2}

which is equivalent to

n^2=3p^2.

Thus, 3 divides n^2 and necessarily 3 must divide n. Hence, n=3q where q is a non negative integer.

Notice that

\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}.

The above equality means that the fraction \frac{m}{n} is reducible, what contradicts our initial assumption. So, \sqrt{3} is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

k=\frac{k}{1}.

Then,

k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}.

Notice that the product mk is an integer. Thus, the fraction \frac{mk}{n} is a rational number. Therefore, k\cdot r\in\mathbb{Q}.

3. Let us prove by <em>reductio ad absurdum</em> that the sum of a rational number and an irrational number is an irrational number. So, we have x is irrational and p\in\mathbb{Q}.

Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

7 0
3 years ago
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