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Murrr4er [49]
3 years ago
11

Fifty dash two percent of people in a certain country like to cook and 54​% of people in the country like to​ shop, while 28​% e

njoy both activities. What is the probability that a randomly selected person in the country enjoys cooking or shopping or​ both? The probability that a randomly selected person in the country enjoys cooking or shopping or both is
Mathematics
1 answer:
Savatey [412]3 years ago
6 0

Answer:

78%

Step-by-step explanation:

Given the information, we can write:

P(cook) = 52%

P(shop) = 54%

P(cook and shop) = 28%

Now, we need to find P(cook or shop).

We need probability formula for general addition rule, which is:

P(A or B) = P(A) + P(B) - P(A and B)

We can take "cooking" and Event "A" and "shopping" as Event "B".

Thus, we write:

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.52 + 0.54 - 0.28

P(A or B) = 0.78

Which is 78%

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Answer:

A) \dfrac{11}{23}

B) \dfrac{88}{345}

Step-by-step explanation:

A survey of 46 college athletes found that

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  • 22 played basketball.

A) If we pick one athlete survey participant at random,  the probability they play basketball is

P_1=\dfrac{22}{46}=\dfrac{11}{23}

B) If we pick 2 athletes at random (without replacement),

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Thus, the probability we get one volleyball player and one basketball player is

P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}

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