Answer:
See below for answers (in bold) and explanations
Step-by-step explanation:
Part A: (h+t)(x) = h(x) + t(x) = (2x-5) + (6x+4) = 2x - 5 + 6x + 4 = 8x - 1
Part B: (h*t)(x) = h(x) * t(x) = (2x-5) * (6x+4) = (2x)(6x) + (2x)(4) + (-5)(6x) + (-5)(4) = 12x² + 8x - 30x - 20 = 12x² - 22x - 20
Part C: h(t(x)) = h(6x + 4) = 2(6x + 4) - 5 = 12x + 8 - 5 = 12x + 3
Answer:
(c)
Step-by-step explanation:
3+2+4 = 9, 4+2= 6- 3= 3
Answer:
eleven below zero
Step-by-step explanation:
opposite of -11 =11 so that doesn't work
positive eleven=11 so that doesn't work
eleven greater than zero=11 so that doesn't work
eleven below zer0= -11 so it works
