PLSSS HELP!!!
1 answer:
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Answer:
Step-by-step explanation:
<h3>A.</h3>The equation for the model of the geyser is found by substituting the given upward velocity into the vertical motion model. The problem statement tells us v=69. We assume the height is measured from ground level, so c=0. Putting these values into the model gives ...
h(t) = -16t² +69t
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<h3>B.</h3>The maximum height is at a time that is halfway between the zeros of the function.
h(t) = -16t(t -4.3125) . . . . . has zeros at t=0 and t=4.3125
The maximum height will occur at t=4.3125/2 = 2.15625 seconds. The height at that time is ...
h(t) = -16(2.15625)(2.15625 -4.3125) = 16(2.15625²) ≈ 74.39 . . . feet
The maximum height of the geyser is about 74.4 feet.
Answer:
see the procedure
Step-by-step explanation:
Looking at the graph we have
The graph represent a vertical parabola open upward
The vertex is a minimum
The vertex is the point (-4,-3)
The domain is the interval -----> (-∞,∞)
The Domain is all real numbers
The range is the interval ----> [-3,∞)
The range is all real numbers greater than or equal to -3
The graph is increasing in the interval (-4,∞)
The graph is decreasing in the interval (-∞,-4)
The minimum of the graph is y=-3 occurs at x=-4