<h2><em>
6/49</em></h2>
<h2><u>
Step-by-step solution.</u></h2><h2>
</h2><h2><em>
2/7 × 3/7=?</em></h2>
For fraction multiplication, multiply the numerators and then multiply the denominators to get
<h2><em>
2×3</em></h2><h2><em>
7×7 </em>
=</h2><h2><em>
6/49</em></h2>
<em></em>
This fraction cannot be reduced.
Therefore:
<h2><em>
2/7×3/7=6/49</em></h2>
<h2><u>
Solution by formals.</u></h2>
<u></u>
Apply the<u> fractions formula for multiplication</u>, to
<h2><em>
2/7×3/7</em></h2>
<em></em>
and solve
<h2><em>
2×3</em></h2><h2><em>
7×7</em></h2><h2><em>
=6/49</em></h2>
<em></em>
<h3>
Therefore:</h3>
<h2><em>
2/7×3/7=6/49</em></h2>
<em></em>
<h2><u><em>
Bryannasalaz</em></u></h2>
<u></u>
Answer:
70
Step-by-step explanation:
I hope this is right but the equation is 6r + 60 = 480
So I did 480 subtracted 60 =420 and then I did 420 divided by 6
I hope this is helpful!!!!
Answer:
![1 \frac{1}{2}](https://tex.z-dn.net/?f=1%20%5Cfrac%7B1%7D%7B2%7D)
Any numerator that is greater than the denominator is considered an improper fraction but can be converted to a mixed number.
Mixed numbers look like the fraction shown above.
Hi there! The numbers can be either -15 or 3.
Let the number be represented by X.
![(x + 6) {}^{2} = 81](https://tex.z-dn.net/?f=%28x%20%2B%206%29%20%7B%7D%5E%7B2%7D%20%3D%2081)
First we work out the parentheses.
![{x}^{2} + 12x + 36 = 81](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%2B%2012x%20%2B%2036%20%3D%2081)
Now subtract 81 from both sides.
![{x}^{2} + 12x - 45 = 0](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%2B%2012x%20-%2045%20%3D%200)
Using the sum of 12 and a product of 45 we get.
![(x + 15)(x - 3) = 0](https://tex.z-dn.net/?f=%28x%20%2B%2015%29%28x%20-%203%29%20%3D%200)
AB = 0 gives A = 0 or B = 0
![x + 15 = 0 \: \: or \: \: x - 3 = 0](https://tex.z-dn.net/?f=x%20%2B%2015%20%3D%200%20%5C%3A%20%5C%3A%20or%20%5C%3A%20%5C%3A%20x%20-%203%20%3D%200)
![x = - 15 \: \: or \: \: x = 3](https://tex.z-dn.net/?f=x%20%3D%20-%2015%20%5C%3A%20%5C%3A%20or%20%5C%3A%20%5C%3A%20x%20%3D%203)
Therefore, the numbers are either -15 or 3.