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2 years ago

How to change 12 meters to feet ?

Mathematics

2 answers:

kirill [66]2 years ago

8 0

39.37 ft is the answer

Anuta_ua [19.1K]2 years ago

5 0

Answer:

multiply 12 by 3.28084! It will give you appx 39.37 ft

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There are 30 students in a class and 40% of the class like orange juice how many studesnt love orange juice

Dovator [93]

What is 40% of 30?

first, convert the percent into a decimal
40% = 0.4

then multiply 0.4 with 30

30*0.4 = 12

12 students

any questions?

6 0

3 years ago

Find the difference of 5k?-7k +6 and 3k - 4k+1. 2

PIT_PIT [208]

Answer:

2k-3k+5

Step-by-step explanation:

4 0

2 years ago

Line ef is tangent to circle g at point h. segment gh is a radius of circle g. what can be concluded about triangle fhg?

solong [7]

We know that

A line tangent to a circle is perpendicular to the radius to the point of tangency.
so
Line ef is perpendicular to the segment gh

hence
Triangle FHG is a right triangle

3 0

2 years ago

Read 2 more answers

What is a bank statement

azamat

Answer:

A bank statement can be defined as a record of payments in and out of a bank account.

Step-by-step explanation:

For example, energy providers offer direct debit payments as the amount that is used each month may vary and they take the required amount at each bill. Standing orders are similar to a direct debit except that they are for a fixed amount.

3 0

2 years ago

Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).

Reil [10]

Answer:

Part A) $sin(\alpha)=\frac{4}{7},\ cos(\beta)=\frac{4}{7}$

Part B) $tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) $sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}$

Step-by-step explanation:

Part A) Find $sin(\alpha)\ and\ cos(\beta)$

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sin(\alpha)=cos(\beta)$

Find the value of $sin(\alpha)$ in the right triangle of the figure

$sin(\alpha)=\frac{8}{14}$ ---> opposite side divided by the hypotenuse

simplify

$sin(\alpha)=\frac{4}{7}$

therefore

$sin(\alpha)=\frac{4}{7}$

$cos(\beta)=\frac{4}{7}$

Part B) Find $tan(\alpha)\ and\ cot(\beta)$

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$tan(\alpha)=cot(\beta)$

Find the value of the length side adjacent to the angle alpha

Applying the Pythagorean Theorem

Let

x ----> length side adjacent to angle alpha

$14^2=x^2+8^2\\x^2=14^2-8^2\\x^2=132$

$x=\sqrt{132}\ units$

simplify

$x=2\sqrt{33}\ units$

Find the value of $tan(\alpha)$ in the right triangle of the figure

$tan(\alpha)=\frac{8}{2\sqrt{33}}$ ---> opposite side divided by the adjacent side angle alpha

simplify

$tan(\alpha)=\frac{4}{\sqrt{33}}$

therefore

$tan(\alpha)=\frac{4}{\sqrt{33}}$

$tan(\beta)=\frac{4}{\sqrt{33}}$

Part C) Find $sec(\alpha)\ and\ csc(\beta)$

we know that

If two angles are complementary, then the value of secant of one angle is equal to the cosecant of the other angle

In this problem

$\alpha+\beta=90^o$ ---> by complementary angles

$sec(\alpha)=csc(\beta)$

Find the value of $sec(\alpha)$ in the right triangle of the figure

$sec(\alpha)=\frac{1}{cos(\alpha)}$

Find the value of $cos(\alpha)$

$cos(\alpha)=\frac{2\sqrt{33}}{14}$ ---> adjacent side divided by the hypotenuse

simplify

$cos(\alpha)=\frac{\sqrt{33}}{7}$

therefore

$sec(\alpha)=\frac{7}{\sqrt{33}}$

$csc(\beta)=\frac{7}{\sqrt{33}}$

6 0

3 years ago