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3 years ago

Can Someone Help? Im already failing Math Badly

Mathematics

2 answers:

PilotLPTM [1.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

Remember that when dealing with negative numbers, the numbers closer to zero are larger than those further away that are also negative.

A is saying that -3 is less than -6, this is INCORRECT because -3 is closer to 0 and they are both negative

B is saying that -6 is less than -3 which is CORRECT

C is saying that -6 is larger than -3 which is pretty much the same as one, so INCORRECT

D is saying that 3 is less than -6, positive numbers are larger than negative numbers, so this is INCORRECT

mr_godi [17]3 years ago

3 0

Answer:

Step-by-step explanation:

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Do circles have equal areas

azamat

Answer:

yes

Step-by-step explanation:

if you divide it evenly, it will always be equal

if you divide it in half, it will be equal,

in quarters,

in eigths,

even in millionths

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professor190 [17]

Answer:

Step-by-step explanation:

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State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

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3 years ago

You need to lay communications cable around the perimeter of three offices, each 8' by 10'. How much cable do you need?

ryzh [129]

Answer:

108 units

Step-by-step explanation:

We are given that

Length of each office,l=10 units

Breadth of each office=b=8 units

Total number of office=3

We know that

Perimeter of rectangle= $2(l+b)$

Using the formula

Length of cable for 1 office= $2(10+8)=36units$

Length of cable required for 3 offices= $36\times 3=108$ units

Hence, the required length of cable=108 units

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3 years ago