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Mariulka [41]
2 years ago
5

Rhombus ABCD has a diagonal BD¯¯¯¯¯.

Mathematics
1 answer:
ELEN [110]2 years ago
5 0

Answer:

Solution given:

m∠ADB=(4x−12)°

m∠CDB=(3x+6)°

m∠ADC =?

Since diagonal BD bisect the angle <ADC

so

m∠ADB= m∠ADC

(4x-12)°=(3x+6)°

4x-3x=6-12

x=12+6

x=18°

again.

<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°

So

<u>the m∠</u><u>ADC</u><u> </u><u>=</u><u>1</u><u>2</u><u>0</u><u>°</u>

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