Question

Solve the system of linear equations below.

Answer 1

Answer: x=2, y=7

Step-by-step explanation:

6x+3y=33.................. (1)

4x+y=15.......................(2)

Using elimination method multiply equation one by 1 and equation 2 by 3

6x+3y=33...................(3)

12x+3y=45....................(4)

Eliminating y

We have

6x+3y=33

-

12x+3y=45

The single equation becomes

-6x+0=-12

-6x=-12

Minus cancelled minus

6x=12

x=12/6

x=2

To find y substitute x=2 in equation 1

6x+3y=33

6(2)+3y=33

12+3y=33

3y=33-12

3y=21

y= 21/3

y=7

Answer 2

Answer:

6×2+3×7=33

12+21=33

33=33

equal

4×2+7=15

8+7=15

15=15

equal

x=2,y=7