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2 years ago

8

Connor gathered dry ingredients to make a large pan of brownies. He mixed1 1/4 cups of sugar, 2 2/3 cups of flour and 1 1/6 cups

of nuts together before adding the other ingredients how many cups of dry ingredients did he mix?

1 answer:

sveta [45]2 years ago

3 0

Answer:

5 $\frac{1}{2}$

Explanation:

1. Find a common denominator for the three fractions. A common denominator is a number all three numbers divide into evenly. The lowest common denominator for 4, 3, and 6 is 12.

2. Find the numerators. This can be done by multiplying the current numerators by however many times the old denominator goes into the new denominator.

4 goes into 12 3 times

3 goes into 12 4 times

6 goes into 12 2 times

1 x 3 = 3

2 x 4 = 8

1 x 6 = 6

So, the fractions become:

$1\frac{3}{12} + 2\frac{8}{12} + 1\frac{2}{12}$

3. Add the numerators of the new fractions and keep the denominator the same.

$4 \frac{13}{12}$

4. Convert the improper fraction to a mixed number.

$1 \frac{1}{12}$

5. Finally, add the whole numbers.

1 + 4 = 5

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A sample of bacteria is growing at an hourly rate of 14% according to the exponential growth function. The sample began with 7 b

tatiyna

Answer:

125

Step-by-step explanation:

x(t) = x0 × (1 + r) t

where:

x(t) = the amount of some quantity at time t

x0 = initial amount at time t = 22

r = the growth rate

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3 years ago

A square corner of 16 square centimeters is removed

oee [108]

Option C:

Area of the remaining paper = (3x – 4)(3x + 4) square centimeter

Solution:

Area of the square paper = $9x^2$ sq. cm

Area of the square corner removed = 16 sq. cm

Let us find the area of the remaining paper.

Area of the remaining paper = Area of the square paper – Area of the corner

Area of the remaining = $9x^2-16$

= $(3x)^2-(4)^2$

Using algebraic formula: $a^2-b^2=(a+b)(a-b)$

$=(3x-4)(3x+4)$

Area of the remaining paper = (3x – 4)(3x + 4) square centimeter

Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.

8 0

3 years ago

Read 2 more answers

Andrew [12]

Answer:

There are (63) combinations. The notation means "six choose three". Out of six items (flavors) choose three.

(nk)=n!k!(n−k)!.

(63)=6!3!3!.

Think of it this way. There are 6 ways to choose a flavor. Once you choose, there are 5 ways to choose the next. After that, there are 4 flavors left. which is 6!/3!=6⋅5⋅4⋅3⋅2⋅13⋅2⋅1=6⋅5⋅4=120.

But, you could have chosen {chocolate,vanilla,strawberry} and you get the same combination as {vanilla, strawberry, chocolate} so we have to divide by 3!=3⋅2⋅1=6 to account for the order of choosing.

So the number of combinations of flavors is (63)=1206=20.

<h3>Mark me a brainlist</h3>

7 0

2 years ago

What is the slope of the line that passes through the points M (-3,5) and N (1,8)

zysi [14]

Answer:

m=3/4

Step-by-step explanation:

See the attached above.

Hope it helps :)

4 0

3 years ago

98 POINTS! PLEASE HELP! I been stuck on this assignment for over 2 weeks. My teacher gave me a simple explanation when I asked f

Colt1911 [192]

See the attached picture.

Create an equation for the volume of the box, find the zeroes, and sketch the graph of the function.

The resulting box has a volume

$V(x)=x(8-x)(12-x)=x^3-20x^2+96x$

because the volume of a box is the product of its width $(12-x)$ , length $(8-x)$ , and height $(x)$ .

find the zeroes

You know right away from the factored form of $V(x)$ that the zeroes are $x=0,8,12$ . (zero product property)

sketch the graph of the function

Easy to plot by hand. You know the zeroes, and you can check the sign of $V(x)$ for any values of $x$ between these zeros to get an idea of what the graph of $V(x)$ looks like. See the second attached picture.

Here's what I mean by "check the sign" in case you don't follow. We know $V(x)=0$ when $x=0$ and $x=8$ . So we pick some value of $x$ between them, say $x=1$ , and find that

$V(1)=1(8-1)(12-1)=7\cdot11=77$

which is positive, so $V(x)$ will be positive for any other $x$ between 0 and 8. Similarly we would find that $V(x)$ for $x$ between 8 and 12, and so on.

What is the size of the cutout he needs to make so that he can fit the most marbles in the box?

It's impossible to answer this without knowing the volume of each marble...

If Thomas wants a volume of 12 cubic inches, what size does the cutout need to be?

Thomas wants $V(x)=12$ , so you solve

$x^3-20x^2+96x=12$

While this is possible to do by hand, the procedure is tedious (look up "solving the cubic equation"). With a calculator, you'd find three approximate solutions

$x\approx0.1284$

$x\approx7.6398$

$x\approx12.2318$

but you throw out the third solution because, realistically, the cutout length can't be greater than either of the sheet's dimensions.

What would be the dimensions of this box?

The box's dimensions are ( $x$ in) x ( $8-x$ in) x ( $12-x$ in).

If $x\approx0.1284$ , then $8-x\approx7.8716$ and $12-x\approx11.8716$ .

If $x\approx7.6398$ , then $8-x\approx0.3602$ and $12-x\approx4.3602$ .

8 0

2 years ago