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PSYCHO15rus [73]
3 years ago
11

HELP ME PLEASE !!! please

Mathematics
1 answer:
pav-90 [236]3 years ago
8 0

Answer:

(0,0) and (60,0)

Step-by-step explanation:

because they are the points on the x-axis

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FIND THE AREA AND PERIMETER PLEASE ​
baherus [9]

Answer:

Area = 70    Perimeter = 50

Step-by-step explanation:

I will begin with area.  I can find the area of each figure, then add the areas.

3 • 18 = 54

4 • 4 = 16

Area = 70

For perimeter, I will add the given lengths.

3 + 18 + 7 + 4 + 4 + 14

Perimeter = 50

8 0
3 years ago
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Priya, variable "p", jumped 3 inches more than Xeno, “x”, in a high jump contest. Mai, “m”, jumped three times as many inches hi
IceJOKER [234]

Answer:

Xeno jumped 1 2/3 in

Step-by-step explanation:

if Mai jumped 3 times higher than Priya dividing Mai's 14 by 3 would get Priya's height. Then by subtracting 3 from Priya's height, which is 4 2/3, you get Xeno's height which is 1 2/3 in

4 0
3 years ago
How do you solve the following for x?
EleoNora [17]

Answer:

Step-by-step explanation:

Is called a letter that stands for the number

7 0
4 years ago
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HELP PLEASE HELP MEEEE PLEASEEE
salantis [7]

Answer: a. x=4 b. x=17.5

Step-by-step explanation:

a. 5x/2+1=11

subtract 1 from both sides : 5x/2=10

multiply both sides by 2 : 5x=20

divide both sides by 4 : x=4

b. 2x/7-3=2

add 3 to both sides : 2x/7=5

multiply both sides by 7 : 2x=35

divide both sides by 2 : x=17.5

8 0
3 years ago
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Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
2 years ago
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