Answer:
D. tan(-π/6)
Step-by-step explanation:
The tangent function is periodic with a period of π, so ...
tan(5π/6) = tan(5π/6 ± kπ) . . . for any integer k
For k = -1, we have ...
tan(5π/6) = tan(5π/6 -π) = tan(-π/6)
Volume of a cylinder = π r² h
Let us assume the following values:
radius = 9
height = 10
Volume = 3.14 * 9² * 10
= 3.14 * 81 *10
Volume = 2,543.40
Changes:
radius is reduced to 2/9 of its original size = 9 x 2/9 = 2
height is quadrupled = 10 x 4 = 40
Volume = π r² h
= 3.14 * 2² * 40
= 3.14 * 4 * 40
Volume = 502.40
Original volume = 2543.40 V.S. Volume after change = 502.40
The volume of an oblique cylinder decreased when its radius was decreased to 2/9 of its original size and its height is increased 4 times.
......................... 1/2
3/4(8p+12)+3/8(16p-8)
=3/4[(8p+12)+1/2(16p-8)]
=3/4[8p+12+8p-4]
=3/4[16p+8]
=3/4*8*[2p+1]
=6[2p+1]
=12p+6
