First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial $x^{2}-10x+13$ . We can now use the quadratic formula to solve.

Remember that the quadratic formula is

$\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}$

Substitute the numbers from the equation into the formula.

$\frac{-(-10)+/-\sqrt{(-10)^{2}-4(1)(13) } }{2(1)}$

Simplify:

$\frac{10+/-\sqrt{100-52} }{2}$

$\frac{10+/-\sqrt{48} }{2}$

Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with $5+/-\sqrt{48}$ .

Hope this helps!

6 0

3 years ago

What is 20 divided by two

Tcecarenko [31]

First of all, this shouldn't be in high school category.
Second, 20 divided by 2 is 10. Dividing is like subtraction. You would subtract 20 by 2, and you would find that after 10 times, you will get to zero.

7 0

3 years ago

Read 2 more answers

Answer answer questions please

Katyanochek1 [597]

Answer:

Step-by-step explanation:

it is 4/5ths of the answer towards one and the only other likely answer would seem as though b but b=9/10ths so D.

3 0

2 years ago

Read 2 more answers