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Lana71 [14]
3 years ago
9

The radius of a circle is 19 inches. What is the circle's area? Use 3.14 for ​.

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

A≈1134.11 squared inches

Step-by-step explanation:

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Jim got C candies from the first house and 6 from the second. Altogether Jim has more than 9 pieces of candy. Write and inequali
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C+6 \geq 9. Notice that the sentence says "has more than 9 pieces of candy" meaning that it could be equal to or greater than 9.

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3 years ago
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The value of t∗ for a 95% confidence interval when there are 10 pieces of data is:
Anarel [89]

Answer:

The t-critical value for 95% confidence interval is ±2.2621

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 10

Alpha, α = 0.05

We have to find the value of t-critical at 95% confidence interval.

Degree of freedom = n - 1 = 9

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

The t-critical value for 95% confidence interval is ±2.2621

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3 years ago
185g shared to the ratio of 2:3
Yuliya22 [10]
The smaller share is 2/(2+3)*185 g = 74 g.
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8 0
3 years ago
A particle moves in a straight line so that its velocity at time
riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.  

s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75

Now we can use this value of t to formulate the position function s(t):

s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\

this is the position at time t.

to find the position at t=2

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{31}{4} = 7.75

the position of the particle at time, t =2 is s(2) = 7.75

3 0
3 years ago
3.-7 + 12 +15 =
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a . ,34

b. -17

c. 18

d. 4

e. -52

f. 34

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