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Lana71 [14]
2 years ago
9

The radius of a circle is 19 inches. What is the circle's area? Use 3.14 for ​.

Mathematics
1 answer:
saveliy_v [14]2 years ago
8 0

Answer:

A≈1134.11 squared inches

Step-by-step explanation:

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A square with side length 4 cm represents 20% of a larger figure what is the area of the larger figure?
victus00 [196]
First we are going to find divided by 100 and multiply 20 is equal to four.

We are gonna use x to represent this number.

x/100 * 20 = 4

Solve for x

Therefore x = 20cm

Now that we found x the side of the larger square we are gonna find the area which is side^2.

20 * 20

Therefore the area of the larger square is 400cm^2
8 0
3 years ago
Can someone help me please!!
ratelena [41]

The coordinates of E are (5.75, 0).

<h3>What is midpoint?</h3>

The midpoint is the middle point of a line segment. It is equidistant from both endpoints, and it is the centroid both of the segment and of the endpoints.

Given that, C is the midpoint of AB, D is the midpoint of CB and E is the midpoint of DB.

Formula for coordinates of midpoint,

(x, y) = [(x1+x2)/2, (y1+y2)/2]

Coordinates of C;

(x, y) = (-10+8)/2, (14-2)/2

(x, y) = (-1, 6)

Coordinates of D;

(x, y) = (-1+8)/2, (6-2)/2

(x, y) = (3.5, 2)

Coordinates of E;

(x, y) = (3.5+8)/2, (2-2)/2

(x, y) =  (5.75, 0)

Hence, The coordinates of E are (5.75, 0).

For more references on midpoints, click;

brainly.com/question/28224145

#SPJ1

8 0
9 months ago
Is upside down triangle also polygon
Stolb23 [73]
Yes because its is the same thing with a different view
8 0
2 years ago
Read 2 more answers
Please helllpppp......​
MrRissso [65]

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2, thus

y = 2x + c ← is the partial equation

To find c substitute (- 3, 4) into the partial equation

4 = - 6 + c ⇒ c = 4 + 6 = 10

y = 2x + 10 ← equation of line

6 0
2 years ago
Read 2 more answers
The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
Read 2 more answers
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