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3 years ago

12

To avoid dehydration, a person should drink 8 ounces of water for every 15 minutes of exercise. How much water should Hahn drink

if he bikes for 135 minutes? You MUST show the proportion and your work.

1 answer:

Lostsunrise [7]3 years ago

7 0

Answer:

72

Step-by-step explanation:

1. Proportion:

8/15=x/135

2. Answer is 72

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Find the interest rate r compounded monthly if the principal P = $4,300 reaches the future value F = $4,720 in t = 6 years. Roun

kirza4 [7]

Answer:

1.55%

Step-by-step explanation:

Fill in the values and solve for the rate using the future value formula.

FV = P(1 +r/n)^(nt)

4720 = 4300(1 +r/12)^(12·6)

(4720/4300)^(1/72) = 1 +r/12

r = 12(4720/4300)^(1/72) -1) ≈ 0.015542

The annual interest rate is about 1.55%.

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3 years ago

The graph of a quadratic function has roots at -3 and -7 and a vertex at (-5, 4). What is the equation of the function in vertex

melomori [17]

Answer:

y = -(x + 5)² + 4

Step-by-step explanation:

The roots are -3 and -7, so:

y = a (x + 3) (x + 7)

Distribute and complete the square:

y = a (x² + 10x + 21)

y = a (x² + 10x + 25 − 4)

y = a (x² + 10x + 25) − 4a

y = a (x + 5)² − 4a

The vertex is (-5, 4), so a = -1.

y = -(x + 5)² + 4

3 0

3 years ago

If A={2,3,5,7} and B={2,4,6,8} then what is AnB?

gregori [183]

Answer:

A∩B = {2}

Step-by-step explanation:

It asks for the common set of A and B.

<u>There only one element common to both the given sets:</u>

A={2,3,5,7} and B={2,4,6,8} ⇒ A∩B = {2}

6 0

3 years ago

Read 2 more answers

Steve paid $62 for groceries last week. That was $6.75 more then he spent this week. How much did Steve spend this week?

yarga [219]

the answer is to 62-6.75 is 55.25

6 0

3 years ago

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Flying to Kimpala with a tail wind a plane averaged 158km/hr. On the return trip the plane only average 112km/hr. While flying b

lora16 [44]

The speed of wind and speed of plane in still air are 23 and 135 km/h respectively.

<u>Step-by-step explanation:</u>

Let the speed of wind and speed of plane in still air are w and p km/h respectively.

The effective speed on onward journey was

$p+w=158$ ................(1)

The effective speed on return journey was

$p-w=112$ ..............(2)

Adding equation (1) and equation (2) we get,

⇒ $(p+w)+(p-w) = 158+112$

⇒ $2p = 270$

⇒ $p = 135$

Putting value of $p = 135$ in $p+w=158$ we get:

⇒ $p+w=158$

⇒ $135+w=158$

⇒ $w=23$

Therefore ,The speed of wind and speed of plane in still air are 23 and 135 km/h respectively.

3 0

3 years ago