Remember the distance formula




By induction:
It's true for

, since

clearly contains a factor of 3.
Suppose it's true for

, that

is divisible by 3. Then

where

is an integer. This reduces to

and both terms are clearly multiples of 3. We know that

is an integer since we had set

previously, which implies

is a multiple of

. So the statement is true.
Answer:
Mr X
Step-by-step explanation:
his identity is a variable ; it could be anybody of the male gender.
all the other ones denote known designations, i.e, B+ grade
Answer:
2(3x + 7)(2x - 1)
Step-by-step explanation:
You can see it a little easier if you take out a common factor of 2
2(6x^2 + 11x - 7)
The 6 leaves you with a lot of factors, the 7 does not. It only has 2 factors.
Let 6 factor into 2 and 3 and the 7 into 7 and 1
2(3x - 1 )(2x + 7)
Now remove the brackets.
2(6x^2 + 21x - 2x - 7) This obviously does not work but we'll combine like terms anyway.
2(6x^2 + 19x - 7)
So we'll try it again
2(3x + 7)(2x - 1)
2(6x^2 + 14x - 3x - 7) Looks like we have it.
2(6x^2 + 11x - 7)
So the right factors are
2(3x + 7)(2x - 1)
Answer:
Step-by-step explanation:
a= 18 degrees
b= 36 degrees
c= 108 degrees