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Phantasy [73]
3 years ago
7

Given that log x = 3 and log y = 5, find log (x^2)(y^2)- log xy

Mathematics
1 answer:
strojnjashka [21]3 years ago
3 0

Step-by-step explanation:

logx²y² - logxy

= log(x²y²/xy)

= logxy

= logx + logy

= (3) + (5)

= 8.

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If x = 7 and f = 4 and g = 9 and l = 24 and p = 12 and e = 9847493 then what is x ÷ fg X i ÷ p
REY [17]
0.38^• or 7/18. If the x after the g and before the i is a multiplication (btw the ^• is a repeater
3 0
3 years ago
If u-ai + bj and v-ci + dj are vectors, then which of the following statements is not true?
alukav5142 [94]

Answer:

Option C

Step-by-step explanation:

Given that u-ai + bj and v-ci + dj are vectors

We have dot product

u.v = (ai+bj).(ci+dj) hence inner product of u and v.  So option a is true

The dot product of u and v is a scalar is true because dot product is always a scalar

The dot product of u and v is a vector. is false because dot product is only a scalar and has no direction and hence cannot be a vector

The dot product of u and v is given by the expression ac+bd

True because we multiply corresponding i components and j components and add.

So only C is not true.

7 0
2 years ago
Several large bowls are containing various amounts of tangerines on a table. When 12 of the bowls each had 8 more tangerines add
Genrish500 [490]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Question 8: A bicycle shop sold 8 tires for $298.75. What was the cost of 1 tire to the nearest hundredth?
kherson [118]

Answer:

Unitary cost= $37.34 = $37

Step-by-step explanation:

Giving the following information:

Number of tires= 8

Total cost= $298.75

<u>To calculate the unitary value of each tire, we need to use the following formula:</u>

Unitary cost= total cost / number of tires

Unitary cost= 298.75 / 8

Unitary cost= $37.34 = $37

6 0
2 years ago
Answer to this question?
Readme [11.4K]
A midsegment is given by the formula:
\frac{x1+x2}{2} , \frac{y1+y2}{2}

Where x1, x2, y1, and y2 correspond to their respective coordinates. We can do the equation:

\frac{-3+5}{2} , \frac{-1+3}{2}
This gets us a midpoint coordinate of <span>(1,1)

</span>As for distance, it will be found by doing:
\sqrt{(x2-x1)^2+(y2-y1)^2}
We can do the following:

\sqrt{(5-(-3))^2+(3-(-1))^2}
\sqrt{(8)^2+(4)^2}
\sqrt{64+16}
This simplifies to 4 \sqrt{5}

:)
5 0
3 years ago
Read 2 more answers
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