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spayn [35]
3 years ago
6

What is the distance between point A(-3,2) and point B(5,-1)

Mathematics
1 answer:
Gnoma [55]3 years ago
8 0

Remember the distance formula

S=\sqrt{(5+3)^{2}+(-1-2)^{2} }

S=\sqrt{8^{2}+(-3)^{2} }

S=\sqrt{64+9}

S=\sqrt{73}


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Which equation has the solution x = 5?
alexgriva [62]
It would be 32-4x=12
32-4(5)=12
32-20=12
12=12
4 0
3 years ago
Read 2 more answers
Evaluate the expression and write your answer in the form a + bi. 1) (2-6i)+(4+2i)2) (6+5i)(9-2i)3) 2/(3-9i)4) (3 − 5i)(7 − 2i)
laiz [17]

Answer:

Step-by-step explanation:

Given the following complex numbers, we are to expressed them in the form of a+bi where a is the real part and b is the imaginary part of the complex number.

1) (2-6i)+(4+2i)

open the parenthesis

= 2-6i+4+2i

collect like terms

= 2+4-6i+2i

= 6-4i

2)  (6+5i)(9-2i)

= 6(9)-6(2i)+9(5i)-5i(2i)

= 54-12i+45i-10i²

= 54+33i-10i²

In complex number i² = -1

= 54+33i-10(-1)

= 54+33i+10

= 54+10+33i

= 64+33i

3) For the complex number 2/(3-9i), we will rationalize by multiplying by the conjugate of the denominator i.e 3+9i

= 2/3-9i*3+9i/3+9i

=2(3+9i)/(3-9i)(3+9i)

= 6+18i/9-27i+27i-81i²

= 6+18i/9-81(-1)

= 6+18i/9+81

= 6+18i/90

= 6/90 + 18i/90

= 1/15+1/5 i

4) For (3 − 5i)(7 − 2i)

open the parenthesis

= 3(7)-3(2i)-7(5i)-5i(-2i)

= 21-6i-35i+10i²

= 21-6i-35i+10(-1)

= 21-41i-10

= 11-41i

4 0
3 years ago
Question 17 *
Anettt [7]
There are 64 boys in the class because 24/3=8 and you have to do the same thing so 8 times 8= 64
6 0
3 years ago
Stephanie sold half of her comic books and then bought five more. She now has 23. How many comic books did she start with?
yulyashka [42]

Answer:

9 comic books

Step-by-step explanation:

23 - 5 = 18

18/2 = 9 comic books

8 0
3 years ago
Use the quadratic formula to solve the equation <br><br> x^2-3x+2=0
Flura [38]

Answer:

x= 1, 2

Step-by-step explanation:

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}. Here a=1, b=-3, and c=2.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{3+/-\sqrt{(-3)^2-4(1)(2)} }{2(1)}=\frac{3+/-\sqrt{9-8} }{2)}

\frac{3+/-\sqrt{1} }{2}=\frac{3+/-\sqrt{1} }{2}=\frac{3+/-1 }{2}= 2 , 1

3 0
3 years ago
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