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zysi [14]
2 years ago
9

WHOEVER ANSWERS THIS CORRECTLY I'LL GIVE BRAINLIEST!!!!!!!!!!!!

Mathematics
2 answers:
Anni [7]2 years ago
7 0

Answer:

10^10

Step-by-step explanation:

10^5+10^5=the exponents are 10^10.

mars1129 [50]2 years ago
7 0

Answer:

The power of 10 would be 5 as well

Step-by-step explanation:

We have 8.3*10^{5} =830000\\

and 1.2*10^{5}=120000

if we subtract them we get 830000-120000=710000\\

and 710000=7.1*10^{5}

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The nurse needs to mix 2% solution with 10% solution to get 10 ml of the prescribed 6% solution. What amount of each solution do
xenn [34]

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

\texttt{ }

<em>Let:</em>

<em>Volumes of 2% Solution = x</em>

<em>Volumes of 10% Solution = y</em>

\texttt{ }

<em>Total Volume = 10 ml</em>

\boxed{x + y = 10} → <em>Equation 1</em>

\texttt{ }

<em>The nurse needs to mix 2% solution with 10% solution to get 10 ml of the prescribed 6% solution</em>.

2 \% x + 10 \% y = 6 \% (10)

2x + 10y = 6(10)

\boxed{x + 5y = 30} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1 - Equation 2:</em>

( x + y ) - ( x + 5y ) = 10 - 30

-4y = -20

y = -20 \div -4

y = 5 \texttt{ ml}

\texttt{ }

x + y = 10

x + 5 = 10

x = 5 \texttt{ ml}

\texttt{ }

<h2>Conclusion:</h2>

<em>Volumes of 2% Solution = </em><em>5 ml</em>

<em>Volumes of 10% Solution = </em><em>5 ml</em>

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

6 0
3 years ago
Elena is a hairdresser, and she usually charges 35$ for a standard haircut. If a customer leaves a 20% tip for a standard haircu
Rashid [163]

Answer:

The Tip is $7.

Step-by-step explanation:

20% of 35$ is 7$.

8 0
2 years ago
Read 2 more answers
A stack of books is 5 feet 1 inch high. How high is it in inches?
zhannawk [14.2K]

Answer:

61 Inches

Step-by-step explanation:

<em>A foot is 12 inches. </em>

1. Multiply 12 by 5.

12*5=60

2. Add the extra inch.

60+1=61

<em>The stack of books is 61 inches high.</em>

3 0
3 years ago
The number of patients treated at Dr. Artin’s dentist office each day was recorded for nine days. These are the data: 6, 6, 6, 5
klemol [59]

Answer:

D) 5.6, 6, 6, 1

Step-by-step explanation:

Before we start solving this problem, we need to first rearrange the provided data from smallest to greatest, so we get:

5, 5, 5, 5, 6, 6, 6, 6, 6

now we can find the mean. The mean is nothing but the average of the provided values, so we need to add them and then divide them into the total amount of data:

mean=\frac{5+5+5+5+6+6+6+6+6}{9}=5.6

next, in an odd number of data, the median is the middle number when written in order. In this case the middle number (the one in the position 5) is 6, so:

median=6

the mode will tell you what is the value that has the greatest number of occurrencies. This is the number that appears the most on our list.

Mode=6

and the range is the difference between the greatest value and the smallest value:

Range=6-5=1

so the answer is D.

6 0
3 years ago
A tennis player moves in a straight-line path as shown in the figure below. find her average velocity in the following time inte
Andreyy89
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval. 

<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>

<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>

<span>average velocity from 2.5 to 4.0s= 0m/s </span>

<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>

<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>

<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>

<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>

<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>

<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>

<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
<span>= (3/5)m/s </span>
4 0
3 years ago
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