Question

If VT=2,what is the length of PT?

Answer 1

Step-by-step explanation:

$\underline{ \underline{ \text{Given : }}}$

• Perpendicular ( P ) = VT = 2
• Base ( b ) = PT
• $\theta = \tt{60 \degree}$

$\underline{ \underline{ \text{Solution}}} :$

$\tt{ \tan(60 \degree) = \frac{perpendicualar}{base}}$

⟶ $\tt{ \sqrt{3} = \frac{2}{PT}}$

⟶ $\tt{ \sqrt{3} \: PT= 2}$

⟶ $\tt{PT = \frac{2}{ \sqrt{3}} }$

⟶ $\tt{PT= \boxed{\tt{ \frac{2 \sqrt{3} }{{3} }}}}$

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