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seraphim [82]
2 years ago
5

Leslie drank 51 ounces of water in 6 hours. At this rate, how much water did Leslie drink in one hour?

Mathematics
2 answers:
Leona [35]2 years ago
7 0

Answer:

The correct answer is <u>8.5 ounces</u> in the matter of one hour

Step-by-step explanation:

To get this answer you will need to use <u>division.</u>

  1. Divide 51 with 6

51 divided by 6 will be 8.5 as a decimal

  • Therefore the correct answer is 8.5

In which was being drank in the matter of one hour

adelina 88 [10]2 years ago
5 0

Answer:

She drank 10.67 oz in one hour.

Step-by-step explanation:

You would multiply the total oz of water drank by the hours.

51 ÷ 6 = 10.6666...

Then you would round it up to 10.67.

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sertanlavr [38]
I hope this helps. If not, feel free to leave a feedback. also leave a comment if it helped.

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4 years ago
What is the volume of the prism
almond37 [142]

The volume of a rectangular prism or cube is: Length × Width × Height

In this case,

- the length of the prism is 2 feet

- the width of the prism is 1.5 feet

- the height of the prism is 1.5 feet

Multiply the above to find the volume: 2 × 1.5 × 1.5 = 4.5 ft³

Keep in mind that volume is represented in cubic units!

4 0
3 years ago
Read 2 more answers
Can some one help me ‼ pleasee ‼
marshall27 [118]

Answer:

12

Step-by-step explanation:

The 2 lines are equal in length. Therefore:-

ST = 21 - 9 = 12

7 0
4 years ago
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 111.4-cm and a standard dev
Kipish [7]

Answer:

P(111.2-cm < ¯ x < 111.4-cm) = 0.4726

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 111.4, \sigma = 0.5, n = 23, s = \frac{0.5}{\sqrt{23}} = 0.1043

Find the probability that the average length of a randomly selected bundle of steel rods is between 111.2-cm and 111.4-cm.

This is the pvalue of Z when X = 111.4 subtracted by the pvalue of Z when X = 111.2. So

X = 111.4

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{111.4 - 111.4}{0.1043}

Z = 0

Z = 0 has a pvalue of 0.5.

X = 111.2

Z = \frac{X - \mu}{s}

Z = \frac{111.2 - 111.4}{0.1043}

Z = -1.92

Z = -1.92 has a pvalue of 0.0274.

0.5 - 0.0274 = 0.4726

P(111.2-cm < ¯ x < 111.4-cm) = 0.4726

5 0
3 years ago
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