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lbvjy [14]
3 years ago
12

Help! What’s the answer? I’m stuck on this question

Mathematics
2 answers:
atroni [7]3 years ago
5 0
The slope would be positive 13/6
sergejj [24]3 years ago
5 0

Answer:

C. \frac{13}{6}

Step-by-step explanation:

formula for slope is \frac{y2-y1}{x2-x1}

So,

\frac{6-(-7)}{1-(-5)}

which leaves you with

\frac{13}{6}

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0.2.0.4, 0.6, 0.8, 1....<br> Arithmetic or geometric
Basile [38]

Arithmetic sequences have a common difference between consecutive terms.

Geometric sequences have a common ratio between consecutive terms.

Let's compute the differences and ratios between consecutive terms:

Differences:

0.4-0.2 = 0.2,\quad 0.6-0.4=0.2,\quad 0.8-0.6=0.2,\quad 1-0.8=0.2

Ratios:

\dfrac{0.4}{0.2}=2,\quad \dfrac{0.6}{0.4} = 1.5,\quad \dfrac{0.8}{0.6} = 1.33\ldots, \quad\dfrac{1}{0.8}=1.25

So, as you can see, the differences between consecutive terms are constant, whereas ratios vary.

So, this is an arithmetic sequence.

3 0
3 years ago
Write an inequality for the graph below.<br> 'न<br> 34<br> 10<br> ।। 12 13 14
Rzqust [24]

Answer:

i like cheese wbu hahahahahaha

5 0
3 years ago
A group of 6 students was playing a game. Each student had a score of -90 at the end of the first round. What was the total of t
Butoxors [25]

Answer:

it means poop

Step-by-step explanation:

8 0
3 years ago
Determine the lateral area and surface area of the given prism. Round answers to the nearest whole number.
vazorg [7]

Answer:

Lateral Area = Area of 2 triangle + Area of slant rectangle + area of back rectangle

Lateral Area = (5m)(3m) + (6m) (36m) + (3m) (36m)

LA = 15m² + 216m² + 108m²

LA = 339 m²

SA = (5m)(3m) + (6m) (36m) + (3m) (36m) + (5m)(36m)

SA = 15m² + 216m² + 108m² + 180 m²

SA = 519 m²

3 0
3 years ago
D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x
MA_775_DIABLO [31]
The solution depends on the value of k. To make things simple, assume k>0. The homogeneous part of the equation is

\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0

and has characteristic equation

r^2-16k=0\implies r=\pm4\sqrt k

which admits the characteristic solution y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}.

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be y_p=ae^{4x}+be^x. Then

\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x

So you have

16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x
(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x

This means

16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}
b(1-16k)=30\implies b=\dfrac{30}{1-16k}

and so the general solution would be

y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x
8 0
3 years ago
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