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3 years ago

Can you prove that def=hgf? Justify your answer.

Mathematics

1 answer:

stellarik [79]3 years ago

5 0

The image is needed so I can work this out

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Thepotemich [5.8K]

Answer:

4.5

Step-by-step explanation:

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3 years ago

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You don’t need to tell me the answer, but could you tell me the formula on how to get the answer ?

steposvetlana [31]

Formula used: cos(x) = $\frac{adjacent}{hypotenuse}$

Hope this helped!

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4 years ago

What equation passes through the point (2,-1) and has a slope of -3

zubka84 [21]

Answer:

one point (2,-1) with a slope of -3

the equation is based on Y=mx+c

#before that equation We have to find y-intercept which is C here

✔ Y=mx+c here x=2, y=-1 and m(slope) =-3

y=mx+c = -1= -3(2) +c= -1= -6+c

there c=5

# Now we can form the equation since we have solved C

✔Y=mx+c = y= -3x+5

8 0

3 years ago

Reduce 240 in the ratio 2:3

schepotkina [342]

Answer:

96 , 144

Step-by-step explanation:

Ratio = 2 : 3

2x + 3x = 240

5x = 240

x = 240/5

x = 48

2x = 2*48 = 96

3x = 3*48 = 144

3 0

3 years ago

Which triangles could not be similar to triangle ABC ? triangle a b c where angle b is a right angle. side a b is 15 cm. side b

STALIN [3.7K]

Answer:

option (b) and (d) are correct.

Right triangle J K L with right angle at K. J K is 60 centimeters. J L is 68 centimeters. K L is 32 centimeters.

and Right triangle D E F with right angle at E. D E is 22.5 centimeters. D F is 25.5 centimeters. E F is 12 centimeters.

Step-by-step explanation:

Given : triangle a b c where angle b is a right angle. side a b is 15 cm. side b c is 8 cm. side a c is 17 cm.

We have to select triangle from given options that are similar to ΔABC,

Two triangles are said to be similar when their corresponding sides are in same ratios and their corresponding angles are equal.

Consider : Right triangle J K L with right angle at K. J K is 60 centimeters. J L is 68 centimeters. K L is 32 centimeters.

FINDING CORRESPONDING RATIOS,

$\frac{AB}{JK}=\frac{15}{60}=\frac{1}{4}$

$\frac{BC}{KL}=\frac{8}{32}=\frac{1}{4}$

$\frac{AC}{JL}=\frac{17}{68}=\frac{1}{4}$

Since, ratios are equal. Thus, triangles are similar.

ΔABC ≅ ΔJKL

Consider : Right triangle D E F with right angle at E. D E is 22.5 centimeters. D F is 25.5 centimeters. E F is 12 centimeters.

FINDING CORRESPONDING RATIOS,

$\frac{AB}{DE}=\frac{15}{22.5}=\frac{2}{3}$

$\frac{BC}{EF}=\frac{8}{12}=\frac{2}{3}$

$\frac{AC}{DF}=\frac{17}{25.5}=\frac{2}{3}$

Since, ratios are equal. Thus, triangles are similar.

ΔABC ≅ ΔDEF

Thus, option (b) and (d) are correct.

3 0

4 years ago