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alexandr402 [8]
3 years ago
5

Can you prove that def=hgf? Justify your answer.

Mathematics
1 answer:
stellarik [79]3 years ago
5 0
The image is needed so I can work this out
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What’s 0.2 as a fraction
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Step-by-step explanation:

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−8 (1 + x) + 7x PLEASE HELP
Tanya [424]

Answer:

-8-x or -x-8 or x=-8

Step-by-step explanation:

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-8-8x+7x

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3 years ago
Let f: R --> R Prove that f is continuous on R iff f-1(H) is a closed set whenever H is a closed set
Anvisha [2.4K]

Answer with Step-by-step explanation:

We are given that a function is a continuous on R

f:R\rightarrowR

We have to prove that if function is continuous ton R iff inverse image of closed set H is closed.

Let H be a closed set and function is continuous  then R-H is a opens set

f^{-1}(R-H)=f^{-1}(R)-f^{-1}(H)=R-f^{-1}(H)=Open set

When function is continuous then inverse image of open set is open

Hence, f^{-1}(H)is a closed set

Conversely,

Let inverse image of closed set H is closed

If H is closed set then R-H is open set

f^{-1}(R-H)=f^{-1}(R)-f^{-1}(H)=R-f^{-1}(H)

When inverse image of closed set is closed then R-inverse image of H is opens set

When inverse image of open set is open then  the function is continuous.

Hence, function is continuous.

Hence proved.

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4 years ago
The x coordinate of the point that contains is always 0
valkas [14]
The x coordinate of the point that contain always zero is- 0
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4 years ago
Read 2 more answers
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