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Fittoniya [83]
2 years ago
12

Can someone please help me with math.

Mathematics
1 answer:
spin [16.1K]2 years ago
7 0

Answer:

neither positive nor negative

Step-by-step explanation:

In order to identify a type of correlation the points have to form where we can draw a line through the points and most of the points will be near that line drawn.

Because most of the points graphed are scattered we cannot identify if it has a positive or negative correlation

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Elena has some bottles of water that each holds 17 fluid ounces.How much water is in 51 bottles.
Kitty [74]
Answer: 867

because
if 1 bottle is 17 fluid ounces
than if you multiply 51 bottels
with 17 fluid ounces it gives you
867 fluid ounces.

51 * 17 = 867
3 0
3 years ago
Read 2 more answers
Try to sketch by hand the curve of intersection of the parabolic cylinder y = x2 and the top half of the ellipsoid x2 + 7y2 + 7z
vovikov84 [41]

Plug y=x^2 into the equation of the ellipsoid:

x^2+7(x^2)^2+7z^2=49

Complete the square:

7x^4+x^2=7\left(x^4+\dfrac{x^2}7+\dfrac1{14^2}-\dfrac1{14^2}\right)=7\left(x^2+\dfrac1{14}\right)^2+\dfrac1{28}

Then the intersection is such that

7\left(x^2+\dfrac1{14}\right)^2+7z^2=\dfrac{1371}{28}

\left(x^2+\dfrac1{14}\right)^2+z^2=\dfrac{1371}{196}

which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let

x(t)^2+\dfrac1{14}=\sqrt{\dfrac{1371}{196}}\cos t\implies x(t)=\pm\sqrt{\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}}

y(t)=x(t)^2=\sqrt{\dfrac{1371}{196}}\cos t-\dfrac1{14}

z=\sqrt{\dfrac{1371}{196}}\sin t

(Attached is a plot of the two surfaces and the intersection; red for the positive root x(t), blue for the negative)

4 0
3 years ago
Can someone help me find the answers!
PIT_PIT [208]

First answer: 9.342

Second answer: 416.66

3 0
3 years ago
Helpppp give explanation too pleaseee!
olga2289 [7]

Answer:

24

Step-by-step explanation:

You have to add all sides of length to get the perimeter

7 0
3 years ago
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What is the interquartile range of the data set 115, 98, 118, 102, 96, 90, 125, 94, 85, 100, 104
kogti [31]

Hello,

interquartile range would be 21

6 0
3 years ago
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