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Sav [38]
3 years ago
8

1. A boulder fell from a small cliff and accelerated towards a car below at 9.8 m/s^2. The

Physics
1 answer:
natita [175]3 years ago
3 0

Answer:

Mass = 10102.04 kilograms.

Explanation:

Given the following data;

Acceleration = 9.8m/s²

Force = 99000N

To find the mass;

Mass = force/acceleration

Mass = 99000/9.8

Mass = 10102.04 kilograms.

Therefore, the mass of the boulder is 10102.04 kilograms.

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A coin is dropped from a height and reaches the ground in 2 seconds. Neglecting air resistance, from what height (in meters) was
Kamila [148]

Answer:

Coin is dropped from a height of 19.62 m

Explanation:

We have given time t = 2 sec

As coin is drop means its initial velocity u = 0 m/sec

We have to find the height from which coin is dropped

From second equation of motion we know that

h=ut+\frac{1}{2}gt^2

So height h=0\times2+\frac{1}{2}\times 9.81\times 2^2=19.62m

So coin is dropped from a height of 19.62 m

3 0
3 years ago
A potter’s wheel moves from rest to an angular speed of 0.20 rev/s in 23.8 s. Assuming constant angular acceleration, what is it
ser-zykov [4K]

Answer:

0.053 rad/s^2

Explanation:

0.2 rev/s = 0.2 rev/s * 2π rad/rev = 0.4π rad/s

Since the angular acceleration is assumed to be constant, and the wheel's angular speed is increasing from rest (0 rad/s) to 0.4π rad/s within 23.8s. Then the angular acceleration must be

\alpha = \Delta \omega / \Delta t = \frac{0.4 \pi - 0}{23.8} = 0.053 rad/s^2

8 0
3 years ago
A clarinet behaves like a tube closed at one end. If its length is 1.0 m, and the velocity of sound is 344 m/s, what is its fund
miv72 [106K]

Answer:

Fundamental frequency = 1376Hz

3 0
4 years ago
A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 44 ft/s2. What is the dist
elena55 [62]

Answer:

Distance, d = 61.13 ft

Explanation:

It is given that,

Initial speed of the car, u = 50 mi/h = 73.34 ft/s

Finally, it stops i.e. v = 0

Deceleration of the car, a=-44\ ft/s^2

We need to find the distance covered before the car comes to a stop. Let the distance is s. It can be calculated using third law of motion as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{0-(73.34\ ft/s)^2}{2\times -44\ ft/s^2}

s = 61.13 ft

So, the distance covered by the car before it comes to rest is 61.13 ft. Hence, this is the required solution.

4 0
4 years ago
Every object in existence has mass. Mass is a measurement of the amount of matter than an object has. Weight and mass, however,
Elan Coil [88]

Answer:

The answer is B

Explanation:

im pretty sure

7 0
3 years ago
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