Question

A coin is dropped from a height and reaches the ground in 2 seconds. Neglecting air resistance, from what height (in meters) was the coin dropped?

Answer 1

Answer:

Coin is dropped from a height of 19.62 m

Explanation:

We have given time t = 2 sec

As coin is drop means its initial velocity u = 0 m/sec

We have to find the height from which coin is dropped

From second equation of motion we know that

$h=ut+\frac{1}{2}gt^2$

So height $h=0\times2+\frac{1}{2}\times 9.81\times 2^2=19.62m$

So coin is dropped from a height of 19.62 m