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aniked [119]
3 years ago
13

2. Another car weighs 2000kg, you can push it .05 m/s?, how much force are you

Physics
1 answer:
Vesna [10]3 years ago
7 0

Answer:

\boxed {\boxed {\sf 100 \ Newtons}}

Explanation:

We are asked to calculate the force you are applying to a car. According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, we can use the following formula to calculate force.

F= m \times a

The mass of the car is 2000 kilograms and the acceleration is 0.5 meters per second squared.

  • m= 2000 kg
  • a= 0.05 m/s²

Substitute the values into the formula.

F= 2000 \ kg \times 0.05 \ m/s^2

Multiply.

F= 100 \ kg *m/s^2

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 100 kilogram meters per second square is equal to 100 Newtons.

F= 100 \ N

You apply <u>100 Newtons</u> of force to the car.

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The 1.5kg ball is launched straight upward with an initial velocity of 7m/s. What is the maximum height it will reach?​
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Answer:

h = 2.5 m

Explanation:

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Mass of a ball, m = 1.5 kg

Initial velocity of the ball, u = 7 m/s

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mgh=\dfrac{1}{2}mu^2\\\\h=\dfrac{u^2}{2g}

Put all the values,

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A celebrated Mark Twain story has motivated contestants in the Calaveras County Jumping Frog Jubilee, where frog jumps as long a
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The frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

To find the answer, we need to know about the time of flight and range of projectile motion.

<h3>What's the expression of range of a projectile motion?</h3>
  • Range = U²× sin(2θ)/g
  • U= initial velocity, θ= angle of projectile and g= acceleration due to gravity
  • U=√{Range×g/sin(2θ)}
  • Here, range= 2.20m, = 36.5°
  • U= √{2.20×9.8/sin(73)}

U= √{2.20×9.8/sin(73)} = 22.5m/s

<h3>What's the expression of time of flight in projectile motion?</h3>
  • Time of flight= (2×U×sinθ)/g
  • So, T= (2×22.5×sin36.5°)/9.8

= 2.73 s

Thus, we can conclude that the frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

Learn more about the range and time period of projectile motion here:

brainly.com/question/24136952

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