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3 years ago

Help me!!! im stuck here if you could help me answer this then please do!!!1

Mathematics

1 answer:

kondaur [170]3 years ago

3 0

Answer:

123.4

Step-by-step explanation:

So I added all of the numbers then divide by how many numbers there was so I divided by 5 because I also counted the x as part of it.

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Help me please i dont understand

ELEN [110]

Answer:

6/5 or 1.2, they're the same value

Step-by-step explanation:

When it says "rate of change", it's really just asking for the slope. If you don't know what the slope is, essentially how much the y-value increases by whenever x increases by 1. This can be formally defined using the equation: $\frac{y_2-y_1}{x_2-x_1}$ which is essentially $\frac{rise}{run}$ . The subtraction is finding the difference between the two numbers to see how much it's changed by. Btw the order doesn't matter, I could plug in (-3, -2) as (x2, y2) or I could plug it in as (x1, y1) as long as I make sure to input it in correctly. In this example I'll just say (-3, -2) = (x1, y1) and (2, 4) = (x2, y2). Plugging these values into the equation gives you: $\frac{4- (-2)}{2- (-3)} = \frac{6}{5}$ that's the rate of change

8 0

2 years ago

Please help ?????????

Murrr4er [49]

Answer:

B is your answer to this problem

Step-by-step explanation:

4 0

3 years ago

Consider the following hypothesis test: H0: LaTeX: \mu_1-\mu_2=0μ 1 − μ 2 = 0 Ha: LaTeX: \mu_1-\mu_2\ne0μ 1 − μ 2 ≠ 0 The follow

Pavel [41]

Answer:

$z=\frac{104-\bar 106}{\sqrt{\frac{8.4^2}{80}+\frac{7.6^2}{70}}}}=-1.53$

Step-by-step explanation:

Data given and notation

$\bar X_{1}=104$ represent the mean for the sample 1

$\bar X_{2}=106$ represent the mean for the sample 2

$\sigma_{1} =8.4$ represent the population standard deviation for the sample 1

$\sigma_{2}=7.6$ represent the population standard deviation for the sample 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

H0: $\mu_{1}-\mu_{2} =0$

H1: $\mu_{1} -\mu_{2} \neq 0$

If we analyze the size for the samples both are greater than 30 and we know the population deviations so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

First we need to calculate the mean and deviation for each sample, after apply the formulas (2) and (3) we got the following results:

And with this we can replace in formula (1) like this:

$z=\frac{104-\bar 106}{\sqrt{\frac{8.4^2}{80}+\frac{7.6^2}{70}}}}=-1.53$

7 0

3 years ago

Let f ( ) sin(arctan ) x x = . What is the range of f ?

nikklg [1K]

So you have composed two functions,
h(x)=sin(x) and g(x)=arctan(x)
→f=h∘g
meaning
f(x)=h(g(x))
g:R→[−1;1]
h:R→[−π2;π2]
And since
[−1;1]∈R→f is defined ∀x∈R

And since arctan(x) is strictly increasing and continuous in [-1;1] ,
h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]
Meaning
f:R→[arctan(−1);arctan(1)]=[−π4;π4]
so there's your domain

5 0

3 years ago

Define two terms, each containing the variables x and y, with exponents on each. (For example: 10x3y−5.) Find the quotient of th

Serjik [45]

Answer:Two such terms are 7x^3*y^9 and -3x*y^5

Their quotient is

7x^3*y^9

--------------

-3x*y^5

This can be simplified as follows:

The numerical coefficients become -7/3.

x^3/x = x^3*x^1 = x^(3 - 1) = x^2 (we subtract the exponent of x in the denominator from the exponent of x in the numerator).

Next, y^9*y^5 = y^4.

The quotient in final reduced form is then (-7/3)x^2*y^4

7 0

3 years ago