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2 years ago

Use the zero x = 5, to help find the remaining zeros of x4 - 4x3 - 14x² + 36x + 45. Select one:

Mathematics

1 answer:

zepelin [54]2 years ago

5 0

Answer:

huh

Step-by-step explanation:

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The set of numbers 1, 7, 11 and 36 contains values for m. What value of m makes the equation below true?

Arada [10]

Answer:

Step-by-step explanation:

If m was 1, then it would be

4 +8 = 36, which is not true.

If m was 7, then it would be

28 + 8 = 36, which is true.

If m was 11, then it would be

44 + 8 = 36, which is not true.

If m was 36, then it would be

144 + 8 = 36, which is not true.

Hope that helps!

7 0

3 years ago

If you multiply four negative numbers, what is the sign of the product?

mestny [16]

Answer:

positive

Step-by-step explanation:

(-a) (-a) (-a) (-a) = a

(-a)(-a) = a

a (-a) = -a

-a (-a) = a --> positive sign

7 0

2 years ago

Read 2 more answers

Find x in this proportion. x/3 = x+2 /5 x = -1 1 2 3

timama [110]

Answer:

it 2

Step-by-step explanation:

i took the test

7 0

3 years ago

Read 2 more answers

Is anyone able to give a step by step process to this?

Thepotemich [5.8K]

Answer:

The value of y is 3 cm.

Step-by-step explanation:

Given,

Perimeter of triangle = $29\ cm$

Solution,

Lets redraw the triangle with nomenclature ABC, given in the attachment.

∴P(ΔABC) = 29 cm (P stands for perimeter)

Length of AB = $y+9$

Length of BC = $2y$

Length of CA = $4y-1$

Now, we all know that the perimeter of a triangle is sum of all the three sides of triangle.

P(ΔABC) = Length of AB+Length of BC+Length of CA

On substituting the values, we get;

$(y+9)+2y+(4y-1)=29\\y+2y+4y+9-1=29\\7y+8=29\\7y=29-8\\7y=21\\y=\frac{21}{7} =3\ cm$

Length of AB = $y+9=3+9=12\ cm$

Length of BC = $2y=2\times3=6\ cm$

Length of CA = $4y-1=4\times3-1=12-1=11\ cm$

Hence the value of y is 3 cm.

8 0

3 years ago

PLEASSSEEEE HELLLLP MEEEE!

Vanyuwa [196]

Answer:

1) C = 3

2) B = 5

3) C = 8

Step-by-step explanation:

Question 1)

We have:

$(2x+3)(4x-1)$

Distribute:

$=(2x+3)(4x)+(2x+3)(-1)$

Distribute:

$=8x^2+12x-2x-3$

Combine like terms:

$=8x^2+10x-(3)$

Therefore, C = 3.

Question 2)

We have:

$(x+2) (2x^2+x-1)$

Distribute:

$\displaystyle =(x+2)(2x^2)+(x+2)(x)+(x+2)( - 1)$

Distribute:

$=(2x^3+4x^2)+(x^2+2x)+(-x -2)$

Combine like terms:

$=2x^3+(5)x^2+x-2$

Therefore, B = 5.

Question 3)

We have:

$(x+2)(x^2-3x-2)$

Distribute:

$=(x+2)(x^2)+(x+2)(-3x)+(x+2)(-2)$

Distribute:

$=(x^3+2x^2)+(-3x^2-6x)+(-2x-4)$

Combine like terms:

$=x^3-x^2-(8)x-4$

So, C = 8.

6 0

2 years ago